Question

6. >>x=[1 2 4 6 12]; >m mean(x) > var(x)

Answer 1

Python Program using numpy:-

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import numpy
x=[1,2,4,6,12]
m=numpy.mean(x)
v=numpy.var(x)
print "Mean of the list is ",m
print "Variance of the list is ",v

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Program Output:-

Execute Embed main.py STDIN 1 import numpy 2 x=[1,2,4,6,12] 3 m-numpy.mean(x) I.lı Result $python main.py Mean of the list is 5.0 Variance of the list is 15.2 4 v numpy.var(x) 5 print "Mean of the list is ",m 6 print "Variance of the list is ",

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Finally mean is-------5

Variance is---------15.2

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Explanation:-

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1.we import numpy to calculate Mean and Variance in python

2.Mean is simply "Average of all numbers"--------------------(1+2+4+6+12)/5=5

3.Formula for variance is below

に!

Steps:-

X1=1,

X2=2,

X3=4,

X4=6,

X5=12

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Mean(u)=5

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Number of items in the list(n)=5

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Square of (1-5)=16

Square of (2-5)=9

Square of (4-5)=1

Square of (6-5)=1

Square of (12-5)=49

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Add all the elements=16+9+1+1+49=76

So finally variance=76/5=15.2

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