1. a) i) P(
>= X) =0.005
df = 28
At = 0.005 and df =
28, from chi-square table, X= 50.993
or using excel function = CHISQ.INV.RT(0.005,28) = 50.993
---------------------
a) ii) P( <=
X) =0.95
= 1-P( >
X) = 0.95
= P( >
X) = 0.05
df = 20
At = 0.05 and df =
20, from chi-square table, X= 31.410
or using excel function = CHISQ.INV.RT(0.05,20) = 31.410
---------------------
b) i) P( <=
44)
= 1-P( >
44)
Using excel function:
=1-CHISQ.DIST.RT(44,20) = 0.9985
-----------------
ii) P( <=
41)
= 1-P( >
41)
Using excel function:
=1-CHISQ.DIST.RT(41,33) = 0.8402
------------------------
If you have any doubt ask me in comments.
At 20 °C, the solubility of KCl is 34 g in 100 g of H 2O. If a student mixes 9.4 g of KCl with 25 g of H 2O at a temperature of 20 °C the solution will start boiling. the solution will be unsaturated. the solution will freeze. KCl will not dissolve in H2O a saturated solution will form.
e the information given about the angle o oso< 2t to find the exact valne in (20) cos(20) c) sin d) cos ž e) tan(2o). fltan Ž 1. Sino=15, ococt 11. tan o="13, TCO < 3/2 find the use the half exact value zl. Sin 22.5 angle formulas to of each expression, 29. sin (-/B)
3 attempts left Complete each nuclear equation. ( Give all nuclei in a. Rb 2o e 30
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ATC $25 Auc $20 HFC-2 FC-? _To if I produce 10 units Arc=25 AVC 2o
7.3 From the generating function formula for the Bessel functions e -1/z) ,(w): for 0 < 2o deduce that ,(w) = ewsin()-nd. (the Schlömilch formula)
7.3 From the generating function formula for the Bessel functions e -1/z) ,(w): for 0
1. A bain Haick concepte wahle (k=0.50 BTR + E) 2o is exposed to Ais at 70.°F (h:- 2.0 BAR) ON one side And Aid Af 20,0F(bag 10.0 WR ) on the eppesite side. Eind the Location MEASURES from the 70E side where the tEMPERATURE is 32.°F.
Find a value of the standard normal random variable z, call it 20, such that the following probabilities are satisfied. a. P(zszo)=0.0502 b. P(-2o Szszo)=0.99 c. P(-zo szszo)=0.90 d. P(- zo szszo) = 0.8062 e. P(-Zo Szs 0) = 0.2593 f. P(-3<z<zo)=0.9654 g. Plz>20) = 0.5 h. Plz szo) = 0.0088
Using the z table (table E) find the critical value (or values) for the case where a=0.01, two tailed test. Using the z table (table E) find the critical value (or values) for the case where a=0.05, right tailed test Using the z table (table E) find the critical value (or values) for the case where a=0.02, left tailed test.
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