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Which would yield propylamine? Two of the above
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Answer #1

1) C2H5Br + NaCN ----> C2H5CN + LiAlH4 ------> C2H5CH2NH2

2)(a) C6H5CONH2 is an acid derivative while C6H5CH2NH2 is an amine

Thus, cold dilute NaOH will react with the acid derivative but not with the amine

(b) Hinsbergs reagent i.e C6H5SO2Cl,OH-, then HCl will be able to distingiush between the primary and seconday amine

c) benzamine (or aniline) will form diazonium salt while cyclohexanamine will not on reaction with NaNO2,HCl

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