Question

A snow plough with a mass of m=8 metric tonnes (1 metric tonne=1,000kg) has an initial speed v1 =14 m/s is clearing snow. The retarding force the snow produces on the snow plough satisfies the force-displacement relationship, Fsnow = 900+6000x2 where Fsnow is in Newtons and x is in metres. Each wheel have a radius of 0.5m and a mass moment of inertia of 3.75 kgm2. Assuming the wheels do not slip and friction can be ignored what is the speed of the snow plough after it travels a distance s=3m?

A snow plough with a mass of m=8 metric tonnes (1 metric tonne=1,000kg) has an initial speed v1 =14 m/s is clearing snow. The retarding force the snow produces on the snow plough satisfies the force-displacement relationship, Fsnow = 900+6000x2 where Fsnow is in Newtons and x is in metres. Each wheel have a radius of 0.5m and a mass moment of inertia of 3.75 kgm2. Assuming the wheels do not slip and friction can be ignored what is the speed of the snow plough after it travels a distance s=3m?

Answer 1

Given that

a mass of m=8 metric tonnes(1 metric tonne=1,000 kg)

v1=14 m/s

F snow=900+6000 x^2

a distance s=3 m

radius of 0.5 m

Answer force on the snow Plough, f= 900+ 6000 ..ale = fim = '18000 [ 900+'booth vor s as de- acteleration here? now, as-vd y torce is refording valvan 1800. [ 200+60002²] - 1800 / 1900 + 6000 x ²) da 33 '12 [v]=14800 ( 960 2 + Gooda] 142 cm-1961- 1800(2100 + 200827) 4/2.-196]> -70.875 0.50798 -70.875 0. Sva - 70.87+98 0.50?= 27.13 2 2 .1 2 >> Ves4.26 N=7.36 IS