Find the number of neutrons released by the following fission reaction. 1 0 n + 235...
Find the number of neutrons released by the following fission reaction.
| 1 |
| 0 |
n +
| 235 |
| 92 |
U ?
| 117 |
| 50 |
Sn +
| 101 |
| 42 |
Mo + neutron(s)
Homework Answers
on the reactants side ::
total number of neutrons = 1 + (235 - 92) = 144
on the product side, number of neutrons = n + (117 - 50) + (101 - 42)
ideally
neutrons on reactants side = neutrons on product side
144 = n + (117 - 50) + (101 - 42)
n = 18
Add Answer to:
Find the number of neutrons released by the following fission
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