You are given Vs = A1.12.cos (100t +B) Vc = A2. Cos (100t + B2) Find...
You are given vs = A1:72.cos (100t + B1) Vc = A2 · cos (100t + B2) Find vr = Az · cos (100t + B3) with – 180° 5 B3 S 180° + VR . Solve without using a calculator. Given Variables: A1:2V B1:25 degrees A2:2V B2:-20 degrees Determine the following: A3 (V): B3 (degrees):
Please explain how you added the phasors together. You are given vs = A1.v2.cos (100t + B1) Vc = A2 · cos (100t + B2) Find VR = Az · cos (100t + B3) with – 180° 5 B3 = 180° + VC Solve without using a calculator. Given Variables: A1:20 B1: 25 degrees A2:20 B2: -20 degrees Determine the following: A3 (V): B3 (degrees):
vs(t) = A1 cos(1000t + B1) (a) Find the instantaneous power supplied by the power supply p = A2V3+ Az cos(2000t + B3) with –180° < B3 5 180 (b) Find the instantaneous power received by the inductor p = A4V3+ As cos(2000t + B5) with –180º < B5 S 180 vs RV3 = Given Variables: A1:10 V B1: 90 degrees R: 4 ohm C:250 uF L:2mH
vs(t) = A cos(1000t + B1) (a) Find the instantaneous power supplied by the power supply p = A2V3+ A3 cos(2000t + B3) with-180° < B3 S 180 (b) Find the instantaneous power received by the inductor p = A4V3 + A5 cos(2000t + B5) with-180° < B5 < 180 Vs RV3 Given Variables: A1:4V B1:30 degrees R:2 ohm C: 500 uF L:2 mH
please also find a4(W) and b4(VAR) (got cut off in the pic), thanks! (t) = A, cos(500+B) Find the complex power S, = +by received by the source Find the complex power S, 4+by received by the resistor Re- Find the complex power S, = s + byl received by the resistors Find the complex power = 14 + he received by the inductor w R Given Variables: A1: 6V B1:45 degrees R1 : 4 ohm R2: 4 ohm L1...
Urgent!! Please label all the answers and find a1,a2,a3 and b1,b2,b3. (1 point) The second order equation x2y" - (x – ķ) y = 0 has a regular singular point at x = 0, and therefore has a series solutio y(x) = Σ CnN+r n=0 The recurrence relation for the coefficients can be written in the form Cn =( DCn-1, n = 1,2, ..., (The answer is a function of n and r.) The general solution can be written in...
Urgent! Please mark all correct answers and find values of a1,a2,a3 and b1,b2,b3. (1 point) The second order equation 3x2y" + 5xy' +(-1x – 1)y = 0 has a regular singular point at x = 0, and therefore has a series solution DO (x) = ± x"+". N=0 The recurrence relation for the coefficients can be written in the form n=1,2,.... C =( ),-1) (The answer is a function of n and r.) The general solution can be written in...
Find A and B1 -1 1+j 21 l1-A^ eB, with 0A, and -180 B, 180 Solve without a calculator Given Variables: a :2 b:2 Determine the following: A1 () B1 (degrees)
LWW is(t) = A1 . cos(1000t +90) + A2 cos(2000t -90) Assume the system is in steady state. Find the current ia at times t1 47 ms: ia (t1) = B1 t2= 5m ms: ia (t2) = B2 kia(t) + R2 Given Variables: A1:9A A2:3A L:2 mH C:500 uF R1:10 ohm R2:2 ohm k:3 V/A Determine the following
Please, multiply the highlighted yellow digit by 6 first then solve. thank you! Given: A4-bit adder is implemented in a carry ripple style as shown in the figure below. B3 A3 B2 A2 B1 A1 BO AO FA c3 FA FA FA CO='1' s2 s1 SO Sought: Please calculate the output carries for each full adder (FA) using A=0x01 and B=0x04. It is required to show ALL incremental steps of the solution, then record each the final results in the...