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Note : value of angle B is -45° which may also be written as 180°-45= 135°. Choose whichever you prefer. However as B = tan-1(1/-1) = 135° is best value. As point (a+jb= -1+J1) lies in 2nd quadrant.
You are given vs = A1:72.cos (100t + B1) Vc = A2 · cos (100t + B2) Find vr = Az · cos (100t + B3) with – 180° 5 B3 S 180° + VR . Solve without using a calculator. Given Variables: A1:2V B1:25 degrees A2:2V B2:-20 degrees Determine the following: A3 (V): B3 (degrees):
You are given Vs = A1.12.cos (100t +B) Vc = A2. Cos (100t + B2) Find VR = Az . cos (100t + B3) with - 180° SB3 S 180° + DR w Solve without using a calculator. Given Variables: A1: 8 V B1: 5 degrees A2:8 V B2: -40 degrees Determine the following: A3 (V): B3 (degrees):
Please explain how you added the phasors together. You are given vs = A1.v2.cos (100t + B1) Vc = A2 · cos (100t + B2) Find VR = Az · cos (100t + B3) with – 180° 5 B3 = 180° + VC Solve without using a calculator. Given Variables: A1:20 B1: 25 degrees A2:20 B2: -20 degrees Determine the following: A3 (V): B3 (degrees):
vs(t) = A cos(1000t + B1) (a) Find the instantaneous power supplied by the power supply p = A2V3+ A3 cos(2000t + B3) with-180° < B3 S 180 (b) Find the instantaneous power received by the inductor p = A4V3 + A5 cos(2000t + B5) with-180° < B5 < 180 Vs RV3 Given Variables: A1:4V B1:30 degrees R:2 ohm C: 500 uF L:2 mH
vs(t) = A1 cos(1000t + B1) (a) Find the instantaneous power supplied by the power supply p = A2V3+ Az cos(2000t + B3) with –180° < B3 5 180 (b) Find the instantaneous power received by the inductor p = A4V3+ As cos(2000t + B5) with –180º < B5 S 180 vs RV3 = Given Variables: A1:10 V B1: 90 degrees R: 4 ohm C:250 uF L:2mH
please also find a4(W) and b4(VAR) (got cut off in the pic), thanks! (t) = A, cos(500+B) Find the complex power S, = +by received by the source Find the complex power S, 4+by received by the resistor Re- Find the complex power S, = s + byl received by the resistors Find the complex power = 14 + he received by the inductor w R Given Variables: A1: 6V B1:45 degrees R1 : 4 ohm R2: 4 ohm L1...
4) Given Variables: c : 2 . Determine the following: a (.) : b (.) : cj CJ Find V1 in cartesian coordinates, i.e., find a and b: Solve without a calculator
Given lines L1 : Ty (1-1)+(21) -2 1 and L2: y 4 8+t2 3 (a) Find the point of intersection of lines Lị and L2. (b) Determine the cosine of the angle between lines L, and L2 at the point of intersection. © Find an equation in form ax +by+cz = d for the plane containing lines L, and Lu. (d) Find the intersection, if any, of the line Ly and the plane P : 3x – 4y + 72...
You are told that the sources in the two circuits below supply the same average power. (a) Find the average power supplied. (b) Find A1. A v2 cos(500t +B) WWW R Given Variables: V1:9 V R: 3 ohm B1: 30 degrees Determine the following: P (W): A1 (V):
a)Find the voltage across inductor L1 at t=0^+ (i.e. just after the switch is opened) b)Determine the voltage across L1 at time = 5us. Problem 11: RL Discharging #2 Determine the voltages of a Resistor- Inductor circuit. Switch S1 has been closed for a long time and the Inductor L1 is completely charged. At time t -0s, Switch S1 is opened. R1 S1 R3 R2 L1 Given Variables Name Value Units E1 14 R1 15 kohm R2 kohm R3 17...