Question

A proposed production system consists of five serial automatic workstations. The processing times at each workstation are constant: 11, 10, 11, 11, and 12 (all times given in this problem are in minutes). The part inter-arrival times are UNIF(13.0, 15.1). There is an unlimited buffer in front of all workstations, and we will assume that all transfer times are negligible or zero. The unique aspect of this system is that at Workstations 2 through 5 there is a chance that the part will need to be reprocessed by the workstation that precedes it. For example, after completion at Workstation 2, the part can be sent back to the queue in front of Workstation 1. The probability of revisiting a workstation is independent in that the same part could be sent back many times with no change in the probability. At present, it is estimated that this probability, the same for all four workstations, will be between 5% and 10%. Develop the simulation model and make six runs of 10,000 minutes each for probabilities of 5, 6, 7, 8, 9, and 10% (i.e., one run for each probability, each with a single replication with a length of 10,000 minutes). Using the results, construct a table (put this table inside your .doe file using an Arena Text box) of the average cycle time (system time) against the probability of a revisit. Also include the maximum cycle time for each run in your table.

Answer 1

UNIF( 13, 15.1) QUEUE ESCAN twall stational Assi GN Create COUNT ASSIGNT FINDI Split GROUP COUNT (DUPLICATE 7 work stations -QUEUE ESCANT

Given that 12 processing times of each work eteetioas'a 11, 10, 11,17 and post interval-time are = (1300, 15.1) time. aroup phos, so it has more wait from the Simulation model, we can see that the world station 2 has to pass through the COUNT , ASSIGN. and the Group phar, so it has As well as we can see that the world station shas lese utilization because it is only used for ossigning By developing the simulation model and by running it We can get the result as. probability cumulative probability category 0.08 6.05 0,06 0.07 0.26 0.08 0.35 0.09

. After Shoulation ILNO category minutes (inmio) 10,000/1 = 909 70,000 110 - 11001 warte station wolle station 2 wolle station - 3 10,000/.41 909 10, Dool!! = 909 10,000/12= .833 woll station 4 wolle stations