Question

In this assignment, you will be creating three static methods as described below:

1. The method duplicate should accept one parameter of type String (named “str”). The method should return a String with every character in str repeated n times, where n is the length of str if str has an odd number of characters

   e.g. duplicate("Hat") should return "HHHaaattt"

   and n is double the length of str if str has an even number of characters

   E.g. duplicate("Hi") should return "HHHHiiii".

   
   

2. isEdhesivePalindrome - The method isEdhesivePalindrome should accept a parameter of type String (named “str”) and return true if str is an "Edhesive Palindrome,” and false otherwise.

   An Edhesive Palindrome must meet the following requirements:

   1. The String parameter str must read the same backward as forwards. (e.g. "racecar" is a valid Edhesive Palindrome). Case does NOT matter. (e.g. "RaceCar" is still valid)
   2. The following characters are equivalent:
      • a ~ 4
      • e ~ 3
      • o ~ 0

      NOTE: The letters are shown in lower-case, but since the case does NOT matter, both 'a' and 'A' is equivalent to '4'. (e.g. "R4ceCar" is still valid)

   3. The String parameter str must be of length greater than 3 and less than 15 (e.g. "R4ceCar" is still valid. But "mom" and "dad" are NOT valid).

   If anyone of these 3 requirements is NOT satisfied, then the String parameter str is NOT considered an Edhesive Palindrome, and the method should return false. If all 3 requirements are satisfied, then the method returns true.

   E.g. using the examples above, isEdhesivePalindrome(“R4ceCar”) should return true, whereas isEdhesivePalindrome(“dad”) and isEdhesivePalindrome(“hello”) should both return false.

3. numberScramble - The method numberScramble should accept one parameter of type double (named “num”) and return a value of type double. If the input parameter is less than 0, return 0.0. Otherwise, the following mathematical operations should be performed on the parameter before returning:
   1. add 5 to num
   2. divide num by 2
   3. square root num

   E.g. numberScramble(3.0) should return 2.0

   Breakdown:

   1. 3.0 + 5 = 8.0
   2. 8.0 / 2 = 4.0
   3. Square root of 4.0 = 2.0

To test your three methods, ask the user for inputs sequentially in your main method and then print out the results of the appropriate method. The output of your main method should match the sample runs below, so you should refer to these examples for the appropriate output.

Sample Run 1

Welcome to the Methods Sampler Platter. Please enter a String to duplicate.
Opera
The duplicated String is: OOOOOpppppeeeeerrrrraaaaa
Next, please enter a String to check for Edhesive Palindromes.
Avid div4
Nice, you found an Edhesive Palindrome!
Almost done! Please enter a number to scramble.
67
The scrambled number is: 6.0

Sample Run 2

Welcome to the Methods Sampler Platter. Please enter a String to duplicate.
Aria
The duplicated String is: AAAAAAAArrrrrrrriiiiiiiiaaaaaaaa
Next, please enter a String to check for Edhesive Palindromes.
palindrome
Too bad, that isn't an Edhesive Palindrome.
Almost done! Please enter a number to scramble.
13
The scrambled number is: 3.0

Answer 1

Note: Could you plz go through this code and let me know if u need any changes in this.Thank You
=================================

// Methods.java

import java.util.Scanner;

public class Methods {

   public static void main(String[] args) {
String dupStr,palStr;
double scrval;
   /*
   * Creating an Scanner class object which is used to get the inputs
   * entered by the user
   */
   Scanner sc = new Scanner(System.in);

        //Getting the input entered by the user
System.out.println("Welcome to the Methods Sampler Platter. Please enter a String to duplicate.");
dupStr=sc.nextLine();

System.out.println("The duplicated String is: "+duplicate(dupStr));
System.out.println("Next, please enter a String to check for Edhesive Palindromes.");
       palStr=sc.nextLine();
           if(isEdhesivePalindrome(palStr))
           {
               System.out.println("Nice, you found an Edhesive Palindrome!");
           }
           else
           {
               System.out.println("Too bad, that isn't an Edhesive Palindrome.");
           }
      
           System.out.println("Almost done! Please enter a number to scramble.");
       scrval=sc.nextDouble();
       System.out.println("The scrambled number is: "+numberScramble(scrval));
      
  
   }

   private static double numberScramble(double d) {
       d+=5;
       d/=2;
       return Math.sqrt(d);
   }

   private static boolean isEdhesivePalindrome(String s) {
       String newStr="";
       if(s.length()<=3 || s.length()>=15)
           return false;
       else
       {
           s=s.toLowerCase();
           for(int i=0;i<s.length();i++)
           {
               if(s.charAt(i)=='4')
               {
                   newStr+='a';
               }
               else if(s.charAt(i)=='3')
               {
                   newStr+='e';
               }
               else if(s.charAt(i)=='0')
               {
                   newStr+='o';
               }
               else if(s.charAt(i)!=' ')
               {
                   newStr+=s.charAt(i);
               }
              
           }
          
           for(int i=0;i<newStr.length()/2;i++)
           {
               if(newStr.charAt(i)!=newStr.charAt((newStr.length()-1)-i))
                   return false;
           }  
       }
      
      
       return true;
   }

   private static String duplicate(String s) {
       String newStr="";
       if(s.length()%2==0)
       {
           for(int i=0;i<s.length();i++)
           {
               for(int j=0;j<s.length()*2;j++)
               {
                   newStr+=s.charAt(i);
               }
           }
       }
       else if(s.length()%2!=0)
       {
           for(int i=0;i<s.length();i++)
           {
               for(int j=0;j<s.length();j++)
               {
                   newStr+=s.charAt(i);
               }
           }
       }
       return newStr;
   }

}

========================================

Output#1:

Welcome to the Methods Sampler Platter. Please enter a String to duplicate.
Opera
The duplicated String is: OOOOOpppppeeeeerrrrraaaaa
Next, please enter a String to check for Edhesive Palindromes.
Avid div4
Nice, you found an Edhesive Palindrome!
Almost done! Please enter a number to scramble.
67
The scrambled number is: 6.0

================================

Output#2:

Welcome to the Methods Sampler Platter. Please enter a String to duplicate.
Aria
The duplicated String is: AAAAAAAArrrrrrrriiiiiiiiaaaaaaaa
Next, please enter a String to check for Edhesive Palindromes.
palindrome
Too bad, that isn't an Edhesive Palindrome.
Almost done! Please enter a number to scramble.
13
The scrambled number is: 3.0

=====================Could you plz rate me well.Thank You