(a) KEi = ½*mv2
= ½* (1.67e-27)*(4.3e3)2
= 1.54e-20 J
(b) using conservation of energy
q V = KE
q 2 ( Q/L) / ( 4 pi eo) ln ( r2/r1) = KE
(1.6* 10^-19)* 2* (6* 10^-12) * 9* 10^9* ln ( 19 / r1) = 1.54e-20
1.728e-20* ln ( 19 / r1) = 1.54e-20
ln ( 19 / r1) = 0.891
Taking antilog on both sides:
19/r1 = 2.44
=> r1 = 7.79 cm (or 0.0779 m)
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