Question

The device at right is used to quickly lift the block shown. The free rope is pulled downward af a constant speed of 2 m/s fo

Solve for all unknown quantities
0 0
Add a comment Improve this question Transcribed image text
Answer #1

IBO WB q=2 m/s

Velocity with which the string is pulled: v_a=2\ m/s for 15 s

Inner and outer diameter of the big pulley 0.4 m 0.9 m

Inner and outer diameter of the small pulley 0.2 m 0.6 m

Outer radius of the big pulley r_{BO}=0.45\ m

Inner radius of the big pulley r_{BI}=0.2\ m

Outer radius of the small pulley r_{SO}=0.3\ m

Inner radius of the small pulley r_{SI}=0.1\ m

Since there is no acceleration on the string, the tension on the string will balance the weight of the block and there are no unbalanced forces. \alpha_1=\alpha_2=a_1=0

Angular velocity of the bigger pulley

[v=r\omega]

Since the velocity is on the inner radius, \omega_1=\omega_B=\frac{v_a}{r_{BI}}=\frac{2}{0.2}=10\ rad/s

The tangential velocity acting of the outer radius of the big pulley,

v_{BO}=\omega_{B}\times r_{BO}=10 \times 0.45=4.5\ m/s [Note- the angular velocity of a rotating object is constant everywhere on it, whereas the tangential velocity at a point depends on the distance of the point from the centre]

The velocity of the part of the string between two pulleys is the same as the velocity of the outer rim of the bigger pulley v_{SI}=v_{BO}

The angular velocity of the smaller pulley,

\omega_2=\omega_S=\frac{v_{SI}}{r_{SI}}=\frac{4.5}{0.1}=45\ rad/s

The velocityof the outer rim of the small pulley,

v_1=v_{SO}=\omega_S\times r_{SO}=45\times 0.3=13.5\ m/s

The equations of motion:

\theta_2=\theta_1+\omega_{B}t [Big pulley]

\theta_2=\theta_1+\omega_{S}t [Small pulley]

r_2=r_1+v_{SO}t [Block]

Since there are no accelerations,

\omega_2=\omega_1=10\ rad/s [Big pulley]

\omega_2=\omega_1=45\ rad/s [Small pulley]

v_2=v_1=13.5\ m/s [Block]

The info:

Big Pulley Small Pulley Block
Event 1 Event 2 Event 1 Event 2 Event 1 Event 2
t_1=0 t_2=15\ s t_1=0 t_2=15\ s t_1=0 t_2=15\ s
\omega_1=10\ rad/s \omega_2=10\ rad/s \omega_1=45\ rad/s \omega_2=45\ rad/s \v_1=13.5\ m/sv_1=13.5\ m/s v_2=13.5\ m/s
\theta_1=0 \theta_2=150\ rad \theta_1=0 \theta_2=675\ rad r_1=0 r_2=202.5\ m
\alpha_1=0 \alpha_2=0 \alpha_1=0 \alpha_2=0 a_1=0 a_2=0
Add a comment
Know the answer?
Add Answer to:
Solve for all unknown quantities The device at right is used to quickly lift the block...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Please show work! A pulley of negligible mass is attached to a block weighing 504 N. A person uses the rope and pulley s...

    Please show work! A pulley of negligible mass is attached to a block weighing 504 N. A person uses the rope and pulley system illustrated in the figure to lift the block at a constant velocity. The pulleys and rope are all ideal. F_G=____________ ? A. Draw the free body diagram for the block. (Observe that three are two rope segments pulling on the block.) B. Apply Newton's first law and determine the tension in the rope, and thus, the...

  • Word Problems You must show all of your work to get full credit. Write as neatly...

    Word Problems You must show all of your work to get full credit. Write as neatly and organized as possible. Put a circle around your final answer. 1.) (10) A cylindrical pulley of mass M 20.0 kg has an inner shaft of radius r 40.0 cm while the outer radius is R 1.00 m, The inner part is attached to the ceiling by a light string and to balance the system the outer part is attached to a mass m...

  • PLEASE EXPLAIN ALL ANSWERS 3 kg vertically cing is 10 kg g is used to frictionless...

    PLEASE EXPLAIN ALL ANSWERS 3 kg vertically cing is 10 kg g is used to frictionless maximum these ag is most 11. Three blocks, A, B, and C. of masses 1, 2, and 3 kg, respectively, are initially at rest on a frictionless surface as indicated in the figure above. What force has to be applied on block C 5= 200 mis? to accelerate the three blocks at 2 m/s? (A) 0.33 N (2) +22) 4362) 16 V=20mis (B) 1.5...

  • i really need help with the graphs Driving Can Be Dangerous to Your Health: An Interrupted...

    i really need help with the graphs Driving Can Be Dangerous to Your Health: An Interrupted Case Study in Physiology Phil Stephens Department of Biology Villanova University Part 1-The Grandparents Arrive Dave pulled the cell phone out of his pocket, cursing himself for not putting it on vibrate. The children, Jason and Laura, were both asleep, and he knew that the rest of the day would not be fun if they were awakened from their naps. "Hi, Dave. We're just...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT