Question

Прr ср. For Questions 1-5 below, consider a propeller aircraft with the following properties. Please take into account whenever PA is used. W = 160,000 N c= 5 x 10-7 m-1 W = 120,000 N e = 0.6 g=9.81 m/s2 S = 60 m2 AR = 10 Po = 1.225 kg/m3 (PA)mazo 2,600 kW = 0.036 Ph=1000 = 1.110 kg/m3 Прr 0.8 Cumax = 1.75 1. (15 points) Find the maximum range of the aircraft at the altitude h = 1,000 m using the Breguet range equation and the time the aircraft will stay in the air for this maximum range flight. In Breguet equations we assume that C and Cp remain constant throughout the flight, which requires speed and/or altitude to change as fuel is consumed. Assuming that the altitude remains constant, also find the initial and final speeds V, and V, corresponding to W, and W1, respectively.

Answer 1

Flight is flying @ Climax Let C = (max - 1,75 Co= Coot KC ² Coot С.2 TARE 2 -0.036+ 1.75 0.1625 T (10) 0.6 Now, AC Breguet Equation en Wo R = h a g Ср Noverall Wf 1000 9.81 1.75 0.1625 n thermal xor x ln 160,000 (20.000 1-75 x x 0.8x en & Assuming (3) R= 1000 9.81 th=1 0.1625 R = 252.6495 m t = - Nov Go h en Wf guo

L zast W, 1.75 = Wo 1.75 - IS V, ²S San87 720,000 1.75= 160,00 0 1.75= Xl.lxv. x60 :!! XV,236 Vo = 406 87 hrs 52.3985 mis V, - 381,74898 45.3784 *= x000 t: - Ci Ср h guo en Wf Nov 1.75 Ion 120000 0.1625 1000 9.81 x 9687817 52.39 160000 =( 0.6225 sec = 4.8225 sec
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