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A large transformer operating at no-load draws an exciting current of 5 A
when the primary is connected to a 240 V, 50 Hz source. From wattmeter test
it is known that the iron losses are equal to 300 W. At short circuit the voltage applied is 24 Volts , the short-circuit current is 35 Amperes, the power meter reads 400 W. Calculate:
i) The reactive power absorbed by the core;
ii) The value of Rc and Xm of the magnetising branch;
iii) The value of Ic and Im ;and
iv) The series impedance of the transformer.
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A large transformer operating at no-load draws an exciting current of 5 A when the primary is connected to a 240 V, 50 Hz source (HELP)
Question 1: A large transformer operating at no-load draws an exciting current of 5 Awhen the primary is connected to a 240 V, 50 Hz source. From wattmeter testit is known that the iron losses are equal to 300 W. At short circuit the voltage applied is 24 Volts , the short-circuit current is 35 Amperes, the power meter reads 400 W. Calculate:i) The reactive power absorbed by the core;ii) The value of Rc and Xm of the magnetising branch; iii)...
Q8. The following data are obtained when open circuit and short circuit tests are performed on...
Q8. The following data are obtained when open circuit and short circuit tests are performed on a single phase, 50 kVA, 2400/240 Volt 50 HZ distribution transformer. VOLTAGE(volts)CURRENT (amperes) POWER (watts) 213 Measurement in low voltage side with high voltage winding open Measurement on high voltage side with low voltage winding shorted 240 5.97 60 20.8 750 (a) Neglecting the series impedance, determine the exciting admittance referred to the high voltage side. (b) Neglecting the exciting admittance, determine the equivalent...
JUST PART E VOLTAGE REGULATION PLEASE!! 2) The series impedance referred to the HV side of...
JUST PART E VOLTAGE REGULATION PLEASE!!
2) The series impedance referred to the HV side of a 30 kVA, 8800/220 V distribution transformer is Zeq = 20 + j80 N. The components of the excitation branch referred to the HV side are Rc = 200 kN and XM = 20 kN. Suppose the transformer is supplying the load connected to the LV winding with the rated apparent power and the rated voltage (220 V) at a 0.8 lagging P.F. Use...
13. The parameters of the equivalents circuit of a 150 kVA, 2400/240 V transformer are: Ri-...
13. The parameters of the equivalents circuit of a 150 kVA, 2400/240 V transformer are: Ri- 0.2 Q, X1= 0.45 Q, X2-4.5 x 103 , R2=2 x 103 Q, Xm= 1.6 k0, Rc 10 kQ as seen from 2400 volts side. Calculate: Open circuit current, power and PF when LV side is excited at rated voltage [23.69 mA; 5.6 W; 0.987] i. The voltage at which the HV side should be excited to conduct a short-circuit test (LV side) with...
[29] SECTION B: TRANSFORMERS QUESTION 2 2.1 A 240:48-volt, 50-F power factor of 0.8 lagging. If...
[29] SECTION B: TRANSFORMERS QUESTION 2 2.1 A 240:48-volt, 50-F power factor of 0.8 lagging. If the no load current and iron loss of this e transformer supplies a load of 10 ampere at a ampere and 12-watt respectively, calculate the total current supplied and the powe oad current and iron loss of this transformer are factor. (7) KVA, 50-Hz, 1200:230-volt single phase transformer has the following series impedance values: Z1 = (0.047 +0.112) Z2 = (0.00172 +0.00411)2 Calculate: 2.2.1...
RT +jX2 N1:N2 +X Is Vjoad +jX V 8000 V (rms) 60HZ When the transformer is open circuited, it produces a secondary volta...
RT +jX2 N1:N2 +X Is Vjoad +jX V 8000 V (rms) 60HZ When the transformer is open circuited, it produces a secondary voltage of 240 V(rms) and source current Is=0.315<81.8° A (rms) a) Find the turms ratio N2/N1 b) Find real and reactive power absorbed by transformer c) Using values obtained in (b) estimate the values of Rc and Xm
RT +jX2 N1:N2 +X Is Vjoad +jX V 8000 V (rms) 60HZ
When the transformer is open circuited, it produces...
three-phase transformer is rated at 12 kV/135 kV, 100 MVA. It has the following equivalent circuit...
three-phase transformer is rated at 12 kV/135 kV, 100 MVA. It has the following equivalent circuit parameters (referred to the primary winding where appropriate) : • primary resistance R1 = 0.03 ohms, secondary resistance R2’ = 0.04 ohms • primary leakage reactance X1 = 0.1 ohms, secondary leakage reactance X2’ = 0.1 ohms • magnetising reactance XM = 16 ohms, core-loss resistance RC = 200 ohms. In your calculations, you should use the simplified equivalent circuit. i) The transformer is...
Question 4 In Figure Q4, a resistance, R is connected in series with an iron-cored choke coil (r in series with L). The circuit draws a current of 5 A at 240 V, 60 Hz. The voltages across the res...
Question 4 In Figure Q4, a resistance, R is connected in series with an iron-cored choke coil (r in series with L). The circuit draws a current of 5 A at 240 V, 60 Hz. The voltages across the resistance and the coil are 100 V and 200 V respectively. Analyze the circuit to determine the following (a) the resistance, reactance and impedance of the coil, (b) the power absorbed by the coil, and (c) the power factor (pf) of...
Question 31 (17 points) 120/120 single-phase transformer. Calculate the values for the equivalent circuit for the single-phase transformer for the given short and open circuit test shown below. (2 po...
Question 31 (17 points) 120/120 single-phase transformer. Calculate the values for the equivalent circuit for the single-phase transformer for the given short and open circuit test shown below. (2 points) Draw the equivalent circuit. (1 point each) Find Ssc, QSC, Soc, Qoc, R1, R2, XI, X2, Rc, Xm, PFsc, PFoc, (esc θ。c) phase angel between V and I. What is the power rating of this transformer? Short circuit test (performed at High Voltage side) Vsc 16.20V rms, Isc 5.00 A...
Rework problem 3.4 if the load connected to the 240-V secondary winding absorbs 110 kVA under...
Rework problem 3.4 if the load connected to the 240-V secondary winding absorbs 110 kVA under short-term overload conditions at an 0.8 power factor leading and at 230 volts. Reference of problem 3.4 A single phase 100-kVA 2400/240-volt 60 Hz distribution transformer is used as a step down transformer. The load, which is connected to the 240-volt secondary winding, absorbs 60kVA at 0.8 power factor lagging and is at 230 volts. Assuming an ideal transformer, calculate the following: a) primary...
Q8. The following data are obtained when open circuit and short circuit tests are performed on a single phase, 50 kVA, 2400/240 Volt 50 HZ distribution transformer. VOLTAGE(volts)CURRENT (amperes) POWER (watts) 213 Measurement in low voltage side with high voltage winding open Measurement on high voltage side with low voltage winding shorted 240 5.97 60 20.8 750 (a) Neglecting the series impedance, determine the exciting admittance referred to the high voltage side. (b) Neglecting the exciting admittance, determine the equivalent...
JUST PART E VOLTAGE REGULATION PLEASE!!
2) The series impedance referred to the HV side of a 30 kVA, 8800/220 V distribution transformer is Zeq = 20 + j80 N. The components of the excitation branch referred to the HV side are Rc = 200 kN and XM = 20 kN. Suppose the transformer is supplying the load connected to the LV winding with the rated apparent power and the rated voltage (220 V) at a 0.8 lagging P.F. Use...
13. The parameters of the equivalents circuit of a 150 kVA, 2400/240 V transformer are: Ri- 0.2 Q, X1= 0.45 Q, X2-4.5 x 103 , R2=2 x 103 Q, Xm= 1.6 k0, Rc 10 kQ as seen from 2400 volts side. Calculate: Open circuit current, power and PF when LV side is excited at rated voltage [23.69 mA; 5.6 W; 0.987] i. The voltage at which the HV side should be excited to conduct a short-circuit test (LV side) with...
[29] SECTION B: TRANSFORMERS QUESTION 2 2.1 A 240:48-volt, 50-F power factor of 0.8 lagging. If the no load current and iron loss of this e transformer supplies a load of 10 ampere at a ampere and 12-watt respectively, calculate the total current supplied and the powe oad current and iron loss of this transformer are factor. (7) KVA, 50-Hz, 1200:230-volt single phase transformer has the following series impedance values: Z1 = (0.047 +0.112) Z2 = (0.00172 +0.00411)2 Calculate: 2.2.1...
RT +jX2 N1:N2 +X Is Vjoad +jX V 8000 V (rms) 60HZ When the transformer is open circuited, it produces a secondary voltage of 240 V(rms) and source current Is=0.315<81.8° A (rms) a) Find the turms ratio N2/N1 b) Find real and reactive power absorbed by transformer c) Using values obtained in (b) estimate the values of Rc and Xm
RT +jX2 N1:N2 +X Is Vjoad +jX V 8000 V (rms) 60HZ
When the transformer is open circuited, it produces...
Question 4 In Figure Q4, a resistance, R is connected in series with an iron-cored choke coil (r in series with L). The circuit draws a current of 5 A at 240 V, 60 Hz. The voltages across the resistance and the coil are 100 V and 200 V respectively. Analyze the circuit to determine the following (a) the resistance, reactance and impedance of the coil, (b) the power absorbed by the coil, and (c) the power factor (pf) of...
Question 31 (17 points) 120/120 single-phase transformer. Calculate the values for the equivalent circuit for the single-phase transformer for the given short and open circuit test shown below. (2 points) Draw the equivalent circuit. (1 point each) Find Ssc, QSC, Soc, Qoc, R1, R2, XI, X2, Rc, Xm, PFsc, PFoc, (esc θ。c) phase angel between V and I. What is the power rating of this transformer? Short circuit test (performed at High Voltage side) Vsc 16.20V rms, Isc 5.00 A...
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