Insert the following keys into the following hash table, size 10: a. our hash function is...
Let 'M' denote the hash table size. Consider the following four different hash table implementations: a. Implementation (I) uses chaining, and the hash function is hash(x)x mod M. Assume that this implementation maintains a sorted list of the elements (from biggest to smallest) for each chain. b. Implementation (II) uses open addressing by Linear probing, and the hash function is ht(x) - (hash(x) + f(i)) mod M, where hash(x)x mod M, and f(i)- c. Implementation (III) uses open addressing by...
5. Hashing (a) Consider a hash table with separate chaining of size M = 5 and the hash function h(x) = x mod 5. i. (1) Pick 8 random numbers in the range of 10 to 99 and write the numbers in the picked sequence. Marks will only be given for proper random numbers (e.g., 11, 12, 13, 14 ... or 10, 20, 30, 40, .. are not acceptable random sequences). ii. (2) Draw a sketch of the hash table...
a. Suppose you are given the following set of keys to insert into a hash table that holds exactly 11 values: 113 , 117 , 97 , 100 , 114 , 123 , 116 , 98 , 99 using the hash function h(item) = item%11 Fill in the following hash table Reference: URL in the Hash tables item 113 is provided since 113%11 = 3 0 1 2 3 4 5 6 7 8 9 10 Hash(item) 113 item b....
10. Submission In this question you will work with a hash table that uses double hashing. The hash table is size 11, the primary hash function is h(K)-K mod 11, and the secondary hash function is hp(K)-(K mod9) +1 Take an empty hash table. Take your student number and split it into 4 2-digit integers. Insert each of these 2-digit numbers in the order in which they appear in your student number into the empty heap. Then insert the values...
Assume a Hash table has 7 slots and the hash function h(k) = k mod 7 is used. The keys 14, 3, 11, 6, 10, 4, 20, and 17 are inserted in the table with collision resolution by chaining. Assume that the keys arrive in the order shown. (a) Show the hash table obtained after inserting all 8 keys. [Show only the final table] (b) Under the assumption that each key is searched with probability 1/8, calculate expected number of...
Part 5. Suppose that your hash function resolves collisions using the open addressing method with double hashing. The double hashing method uses two hash functions h and h'. Assume that the table size N = 13, h(k) = k mod 13, h'(k) = 1 + (k mod 11), and the current content of the hash table is: 0 1 2 3 6 7 8 9 10 11 12 4 17 5 98 If you insert k = 14 to this...
1. Given a hash table with size 10, hash function is hash(k) = k % 10, and quadratic probing strategy is used to solve collisions. Please insert the keys 19, 68, 59, 20, 32, 88, 56 in the hash table. 2. Let T be a binary tree with 31 nodes, what is the smallest possible height of T? What is the largest possible height of T?
Assume data is to be stored in a hash table using the following keys: 62,77.26, 42, 52,76 Assume the hash table size is 7, the hash function used is the modulo function i.e. h/key) = key % table_size, and collisions are handled using linear probing. What's the content of the table after all keys are mapped to the hash table? (List keys starting from table index 0 and on Separate numbers by a comma and a single space, and indicate...
#3 [3 points] Sketch a hash table of size N=11, where the hash function is hash(key) = key mod N and quadratic probing is used to resolve collisions, after the following elements are inserted: 20, 42, 45, 49, 62, 72, 95. The probes are based on this equation: (H+c1∗i+c2∗i2)mod(N) and c1=1, c2=1. If direct hashing was used to store the same elements as the previous problems (20, 42, 45, 49, 62, 72, 95), what should be the minimum size of...
Given the input sequence 4371, 1323, 6173, 4199, 4344, 9679, 1989, a hash table of size b=10, and a hash function h(x)=x mod b, show each step needed to build a hash table A closed hash table using double hashing, with the second hash function as h′(x)=7 − (x mod 7) This yields the sequence of hash functions hi(x)=(x mod b + i⋅ (7 − ( x mod 7)))mod b for i=0,1,…