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A proton is traveling at a speed of 3.0E+7 m/s . The proton needs to circle...
A proton is going 97 m/s when it is exposed to a 15 T magnetic field...
A proton is going 97 m/s when it is exposed to a 15 T magnetic field (see below) and begins moving in a circle. Determine the the radius of the motion, and the period (time to complete one orbit). A proton has a charge of 1.6×10-19 C & a mass of 1.67×10-27 kg. Ignore gravity.
A proton moves in a circle with a speed of 430 m/s through a uniform magnetic...
A proton moves in a circle with a speed of 430 m/s through a uniform magnetic field of 2.0 T directed perpendicular to the circular path. 1) What is the orbital radius of the proton? (Express your answer using two significant figures.) (units in micro m)
A proton is traveling with an initial velocity of (7 x 10^4) m/s in the "i...
A proton is traveling with an initial velocity of (7 x 10^4) m/s in the "i hat" direction and is subject to the gravitational force of the earth. What is the magnitude and direction of the magnetic field needed to keep the proton moving in the x direction if it enters a region of uniform magnetic field.
X 107 kg) 27.25 A proton (q 1.60 x 1019 C, m 1.67 moves in a...
X 107 kg) 27.25 A proton (q 1.60 x 1019 C, m 1.67 moves in a uniform magnetic field B (0.500 T)1. At t = 0 the proton has velocity components ux-1.50 × 105 m/s, vy=0, and vz = 2.00 × 105 m/s (see Example 27.4) (a) what are the magnitude and direction of the magnetic force acting on the proton? In addition to the magnetic field there is a uniform electric field in the +x-direction, E (+2.00 x 104...
4) A proton (q 1.6x10" C. m-1.67 10 kg) is accelerated from rest vo a speed of 5 0x 104 m's then ...
4) A proton (q 1.6x10" C. m-1.67 10 kg) is accelerated from rest vo a speed of 5 0x 104 m's then the proton enters a magnetic neid of 0 080 T oriented perpendioar to its direction of motion (into tha page) al Draw the trajectory of the proton (4) n the magnetic field Which way the does the trajecory curve, lo the left or to the right? Please explain. lin) (7) b) Use conservation af envergy to determine the...
A proton, traveling with a velocity of 3.1 × 106 m/s due east, experiences a magnetic...
A proton, traveling with a velocity of 3.1 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 6.6 × 10-14 N and direction of due south. What are the magnitude and direction of the magnetic field causing the force? If the field is up, then enter a number greater than zero. If the field is down, then enter a number less than zero. An α-particle has a charge of +2e and a mass of...
The figure below shows a proton entering a parallel-plate capacitor with a speed of 2.20×105 m/s....
The figure below shows a
proton entering a parallel-plate capacitor with a speed of 2.20×105
m/s. The proton travels a horizontal distance x = 7.20 cm through
the essentially uniform electric field. The electric field of the
capacitor has deflected the proton downward by a distance of d =
0.760 cm at the point where the proton exits the capacitor. (You
can neglect the effects of gravity.) capacitor.png Using
kinematics, find the vertical acceleration (including sign) of the
proton in...
A proton (g = 1.6 X 10-19 C, m = 1.67 X 10-27 kg) moving with...
A proton (g = 1.6 X 10-19 C, m = 1.67 X 10-27 kg) moving with constant velocity enters a region containing a constant magnetic field that is directed along the z- axis at (x,y) = (0,0) as shown. The magnetic field extends for a distance D = 0.67 m in the x-direction. The proton leaves the field having a velocity vector (Vx, vy) = (2.6 X 105 m/s, 1.2 X 105 m/s). V ---D---- 1) What is v, the...
10. An automobile, traveling at a constant speed of 25 m/s, enters a 90° curve and...
10. An automobile, traveling at a constant speed of 25 m/s, enters a 90° curve and emerges from this curve 68 later. What are the x and y components of average acceleration during this time interval? [Hint: Av, 0 m/s - 25 m/s -25 m/s, Avy - 25 m/s - 0 m/s - 25 m/s.az - Av, /t, a, Av, /t] 11. While jogging this morning you encountered a circular track. As you finished one round along the track with...
X 107 kg) 27.25 A proton (q 1.60 x 1019 C, m 1.67 moves in a uniform magnetic field B (0.500 T)1. At t = 0 the proton has velocity components ux-1.50 × 105 m/s, vy=0, and vz = 2.00 × 105 m/s (see Example 27.4) (a) what are the magnitude and direction of the magnetic force acting on the proton? In addition to the magnetic field there is a uniform electric field in the +x-direction, E (+2.00 x 104...
4) A proton (q 1.6x10" C. m-1.67 10 kg) is accelerated from rest vo a speed of 5 0x 104 m's then the proton enters a magnetic neid of 0 080 T oriented perpendioar to its direction of motion (into tha page) al Draw the trajectory of the proton (4) n the magnetic field Which way the does the trajecory curve, lo the left or to the right? Please explain. lin) (7) b) Use conservation af envergy to determine the...
The figure below shows a
proton entering a parallel-plate capacitor with a speed of 2.20×105
m/s. The proton travels a horizontal distance x = 7.20 cm through
the essentially uniform electric field. The electric field of the
capacitor has deflected the proton downward by a distance of d =
0.760 cm at the point where the proton exits the capacitor. (You
can neglect the effects of gravity.) capacitor.png Using
kinematics, find the vertical acceleration (including sign) of the
proton in...
A proton (g = 1.6 X 10-19 C, m = 1.67 X 10-27 kg) moving with constant velocity enters a region containing a constant magnetic field that is directed along the z- axis at (x,y) = (0,0) as shown. The magnetic field extends for a distance D = 0.67 m in the x-direction. The proton leaves the field having a velocity vector (Vx, vy) = (2.6 X 105 m/s, 1.2 X 105 m/s). V ---D---- 1) What is v, the...
10. An automobile, traveling at a constant speed of 25 m/s, enters a 90° curve and emerges from this curve 68 later. What are the x and y components of average acceleration during this time interval? [Hint: Av, 0 m/s - 25 m/s -25 m/s, Avy - 25 m/s - 0 m/s - 25 m/s.az - Av, /t, a, Av, /t] 11. While jogging this morning you encountered a circular track. As you finished one round along the track with...
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