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The life (in months) of a certain electronic computer part has a probability density function defined by f(t) = ke-Ź, for t i

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Probability

Solution: a. From the given information, f(t) ke. for tin[0, c) 5dt=1 0 ke dt 1 0 1-P -1 - 1 0 -2k(-)1 -2k (0-1) 2k 1 =

Lett be the time. The probability that randomly selected component will last at most 12 months is 1 -e dt - P(ts12) = 0 12 44

The cumulative distribution function is f (x)dx= e d e 2 e - 1-e Il II

d. P(t56)=1-e 6 -1- e2 1-e =1-0.0498 0.9502

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