The wire lies horizontal will not give any field as it lies along the point.
And the vertical wire will contribute to field.
It is near one end of wire and other end is going infinite.
So field will be half of field to that of long wire in the middle at point d away from it.
Field by long wire in middle at point d away from it is,
B *2πd= u0*I, (by Ampere's law )
So B =(u0*I)/2πd
Here d is 'a' in the given problem
And field wil half as it is towards one end of wire.
So finally B for the system is B= 0.5(u0*I)/2πa
Or B = (u0*I)/4πa
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