The region of space between x=0 and x=3.0cm contains an increasing electric field E(x)=E0x/a in the...
Homework Answers
Ex = E0x/a
Ex = 5000a/0.01 = 500000 x
v = Edx
v = 5000 x^2/2
V = 5000* (0.028^2/2 -0.015^2/2)
V = -137.9 volts
V = (integration)Edx
= (integration)(E0x/a)dx
= E0(x^2/2a)
so,
potential diffrence between x=1.5cm and x=2.8cm
= (E0/2a)*[(2.8*10^-2)^2 - (1.5*10^-2)^2]
= (5.0x10^3/0.02)*[(2.8*10^-2)^2 - (1.5*10^-2)^2]
= 139.75 volt
V = (integration)Edx
= (integration)(E0x/a)dx
= E0(x^2/2a)
so,
potential diffrence between x=1.5cm and x=2.8cm
= (E0/2a)*[(1.5*10^-2)^2 - (2.8*10^-2)^2 ]
= (5.0x10^3/0.02)*[(1.5*10^-2)^2 - (2.8*10^-2)^2 ]
= -139.75 volt
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