Question

EXAMPLE 26-1 REFLECTING ON A FLOWER to the leit ofa An observer is at table level, a distance d to the left of a flower of height h. The flower itself is a distance d to as shown in the sketch. Note that a ray of light propagating from the top of the flower to the observer's eye refet. ror at a height y above the table. Find y in terms of the height of the flower, h. PICTURE THE PROBLEM The physical situation is shown in the diagram, along with a ray from the top of the flower to the eye of the observer. The point where the ray hits the mirror is a height y above the table. The flower is a distance d to the left of the mirror and its image is a distance d to the right of the mirror. Finally, the observer's eye is a distance 2d to the left of the mirror STRATEGY To find y, we must use the fact that the angle of reflection is equal to the angle follows, then, that tan 0 obtained from the small yellow triangle must be equal tan 0 equal to one another yields a relation that can be solved for y. of incidence. In the diagram we indicate these two angles by the symbol 6. It to tan 0 obtained from the larger green triangle. Setting these expressions for

How did they come to the conclusion of 2/3h? Thanks!

How did they come to the conclusion of 2/3h? Can someone show me exactly how they got to this number?

Answer 1

2d tlnabove wo hu 씩,

e. ん 2d In A Aog tan 9M 30 Bol al 2. ん ne heonnt moves uwane