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What is the value of K at 298K for the following reaction? (Please give your answer...

What is the value of K at 298K for the following reaction? (Please give your answer to two significant digits in scientific notation) K = enFE°/RT = 10nE°/0.0592

3A2+(aq) + 2B(s)→ 2B3+(aq) + 3A(s)

A2+(aq) + 2e- → A(s) E°red = −0.41 V

B3+(aq) + 3e- → B(s)  E°red = − 0.75 V

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Answer #1

oxidation: 2B ----------------> 2 B+3 + 6e-

reduction: 3 A+2 + 6e- ------------------> 3A

number of electrons transfered =6

Eocell = Eo red - Eo oxd

= -0.41 - (-0.75)

= 0.34 V

delta G = - n FE

delta G = -RT lnK

n F E = R T ln K

6 x 96485 x 0.34 = 8.314 x 298 x ln K

K = 3.2 x 10^34

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