Question

given the following contingency table

	C1	C2	C3	C4
R1	1	2	2	101
R2	2	3	3	101
R3	2	3	2	102
R4	2	2	2	101

Perform chi test of independence of counts on categories at alpha=0.05

Enter pvalue with 3 decimals

Answer 1

Using Minitab, (Stat -> Tables -> Chi Square Test for Association), we get the following output -

Minitab Untitled [Session] File Edit Data Calc Stat Graph Editor Tools Window Help Assistant fix T 01-12-2019 08:46:24 Welcome to Minitab, press F1 for help Chi-Square Test for Association: C1, Worksheet columns Rows: C1 Columns: Worksheet columns C4 с1 All сз с2 101 R1 1 2 106 1.722 2.459 2.213 99.606 R2 2 3 3 101 109 1.770 2.529 2.276 102.425 R3 2 102 109 1.770 2.529 2.276 102.425 R4 2 2 101 107 1.738 2.483 2.234 100.545 All 7 10 405 431 Cell Contents: Count Expected count Pearson Chi- Square = 1.109, DF Likelihood Ratio Chi-Square 9, P-Value = 0.999 = = 1.143, DF = 9, P-Value = 0.999 NOTE 12 cells with expected counts less than 5

Now,

P-value = 0.999

Since P-value > 0.05, so we fail to reject the null hypothesis at 5% level of significance and we can conclude that there is no association between row levels and column levels.