Question

Write a full C++program to do the following processes on a two dimension array of integers. Assume the size is 4x4 .

1- Fill the array with the numbers like this pattern:

1 1 1 1

2 2 2 2

3 3 3 3

4 4 4 4

Note: Do not accept the values as input, or hard code it. Find the math to generate these numbers and fill the array with them.   

2- Reset the main diagonal elements of the array. This means all the elements which fall in the main diagonal will be 0. See this example: The result will be like this:

0 1 1 1

2 0 2 2

3 3 0 3

4 4 4 0

Note: Again find the relationship among these items in the main diagonal and reset them.

3- Create a method named Sum to find the summation of each row of the array. So pass the array and the row number that you want to calculate and return the sum of it.  

Answer 1

#include<iostream>

#include<conio.h>

using namespace std;

const int arr_size = 4;

int arr[arr_size][arr_size] = {0};

/* Method to print array */

void print(){

for(int i = 0; i< arr_size; i++ ){

for(int j =0; j< arr_size; j++){

cout<<arr[i][j]<<" ";

}

cout<<endl;

}

}

/* Method to find sum corresponding to row numbers.

Param In: array[Integer][Integer], row number[Integer]

Output: sum[Integer] of corresponding row

*/

int sum(int arr[arr_size][arr_size], int row){

int sum_row =0;

for(int i = 0; i< arr_size; i++){

sum_row += arr[row-1][i];

}

return sum_row;

}

int main(){

/* First part: Array is generated based upon the row numbers.

So for row 'i' enteries will be 'i' for all columns

Assumption: row will start from index 1 not 0

*/

for(int i = 1; i< arr_size+1; i++){

for(int j = 0; j< arr_size; j++){

arr[i-1][j] = i;

}

}

//Printing array

print();

cout<<endl;

/* Modifying array with main diagonal as zero

RelationShip: For diagonal element i = j or row number = columm number

*/

for(int i = 0; i< arr_size; i++){

arr[i][i] = 0;

}

//Printing array

print();

cout<<endl;

int row;

cout<<"\n Enter the row number for which you need summation: ";

cin>>row;

cout<<"Sum for row number: "<< row<< " ,is: "<<sum(arr, row);

getch();

}

Output: