Question

-What is the molarity of 1.5 N CaCl2?

-You take 1 mL of patient serum and add it to 3 mL of water. Next, you take 1 mL of the dilution you just made and add it to 4 mL of water. You perform a glucose test using this final sample and receive a result of 6 mg/dL.

a. What is the dilution factor of the final sample?

b. Is the patient’s glucose value in the reference range?

Answer 1

Molarity normality is no. of moles dissowed in one litre of solution and es no. of gram equivalents dissowed in one line of NDYm Solution. " ca is 2 . So its equivalent weight will be the valency of Molecular weight . So Normality = 2x Molarity - Molarity - Normality a 0.75M. & Molarity = 0.75M. A me is added with 3 me making a total of 4 ml solution. So dilution is 1:4 Again 1 ml of diluted solution is added to up mL of water making a total of 5 me solution. So again dilution factor = 105. (a) a final dilution factor a txt = 1:20. (6) Glucose concentration in corum = bng/dex 20 = 120 mg/de so it is within referance range which is 40 to 130 mg/dl.