Question

The square cross-section of a frame with a winding number N = 600 has a side a = 50 mm. Frame,
It is in a uniform magnetic field with a size of B = 1.2 T and 250 mA from one winding
current passes. 
(a) find the magnetic dipole moment of the winding; 
(b) Magnetic of the frame if the angle between the dipole moment and B magnetic induction is 37 degrees, the dipole button is magnetic
find the torque; 
(c) What is the potential work of the magnetic dipole in this case?
(d) Rotate 180 degree and steer in the opposite direction. How much work does an external impact need to do?

Answer 1

# a magnetic moment M2 NIA M1 = 600 XCSoX10-32x292x10-3 600 x 2500X10-6x250 810-3 A-mal M = IME 0.375 6 Тота M 35лв T= 0.271 N-m2 (0.375) (1.2) Sin (37) © s potential work sense 5 - MB COLO -60-375) (1.2) Cos (37) LU 0.359 1 work done to ratecte by O =180. W=BM p [ cose] Bm C cos Oq- cose] Oz 0 o 37° 180+373 217 02 w= 10.375) (1.2) [ cos (37) Cos ( 217)] 0.375 X 1.2x 1.59 w= Iw= 0.718 Joule I work done by enternal suport to rotate by Ibood

# a magnetic moment M2 NIA M1 = 600 XCSoX10-32x292x10-3 600 x 2500X10-6x250 810-3 A-mal M = IME 0.375 6 Тота M 35лв T= 0.271 N-m2 (0.375) (1.2) Sin (37) © s potential work sense 5 - MB COLO -60-375) (1.2) Cos (37) LU 0.359 1 work done to ratecte by O =180. W=BM p [ cose] Bm C cos Oq- cose] Oz 0 o 37° 180+373 217 02 w= 10.375) (1.2) [ cos (37) Cos ( 217)] 0.375 X 1.2x 1.59 w= Iw= 0.718 Joule I work done by enternal suport to rotate by Ibood