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in a similar experiment, if we want to buoy a 0.147-kg solid platinum object in water...

in a similar experiment, if we want to buoy a 0.147-kg solid platinum object in water with an attached string from above, what is the tension in Newtons required to support the piece of platinum?

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Answer #1

mass of he solid platinum object m_platinum=0.147 kg

density of platinum, rho_platinum=21450 kg/m^3

volume of the given platimum v=m/(rho_platinum)

now,

buoyancy force FB=m_water*g

FB=(rho_water*V_water)*g

FB=(rho_water*(m_platimum)/(rho_platimum)*g)

FB=(1000*(0.147/(21450))*9.8)

FB=6.72*10^-2 N

and

tension T=(m_platinum*g)-FB

T=(0.147)*9.8-(6.72*10^-2)

T=1.373 N

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