A block of mass m = 2.50 kg is hanging from a massless cord that is wrapped around a pulley (mass = 4.50 kg) as shown in the figure. The cord does not slip relative to the pulley as the block falls. Find the magnitude of the acceleration of the hanging mass. (moment of inertia of the pulley = ½Mr²)
effective mass is 2.5+(4.5/2) = 4.75 Kg
force acting is F = 2.5*9.8 = 24.5 N
using Newton's second law of motion
F = m*a
24.5 = 4.75*a
a = 24.5/4.75 = 5.15 m/s^2
A block of mass m = 2.50 kg is hanging from a massless cord that is...
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