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Suppose a receiver samples its input signal 4800 times a second, measuring properties of the signal. a. Suppose the sampling looks only at signal amplitude: what is the symbol rate? b. Suppose the sampling measures phase (it measures four phase values) so each sample now has four measurements: what is the symbol rate?

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Answer #1

The receiver samples its signal in 4800 times a second means BIT RATE is 4800 bps

Let the modulation factor BPSK=1 then

a) Symbol rate= Bit Rate/(Modulation factor * FEC)

Here sampling looks only at signal amplitude so FEC(Forward Error Correction) will be eliminated and formula will become

Symbol rate= Bit Rate/Modulation factor

= 4800/1

=4800 symbols per second

b) Now sampling measures 4 phase values so FEC will be 1/4 now

Symbol rate= Bit Rate/(Modulation factor * FEC)

= 4800/(1*0.25)

= 19200 symbols per second.

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