Values ( X ) | Σ ( Xi- X̅ )2 | |
23 | 2.0863 | |
26 | 19.7527 | |
21 | 0.3087 | |
19 | 6.5311 | |
16 | 30.8647 | |
22 | 0.1975 | |
23 | 2.0863 | |
19 | 6.5311 | |
25 | 11.8639 | |
Total | 194 | 80.2223 |
Mean X̅ = Σ Xi / n
X̅ = 194 / 9 = 21.5556
Sample Standard deviation SX = √ ( (Xi - X̅
)2 / n - 1 )
SX = √ ( 80.2223 / 9 -1 ) = 3.1667
Test Statistic :-
χ2 = ( ( 9-1 ) * 10.028 ) / 10
χ2 = 8.02
Question 2
Test Statistic :-
f = 8.5 / 4
f = 2.13
A sample of 9 days over the past six months showed that a dentist treated the...
A sample of 9 days over the past six months showed that a dentist treated the following numbers of patients at his dental clinic: 22, 26, 20, 18, 15, 22, 25, 19, and 26. If the number of patients seen per day is normally distributed, would an analysis of these sample data reject the hypothesis that the variance in the number of patients seen per day is equal to 10? Use a 0.10 level of significance. State the null and...
x1 10 19 12 20 16 x2 21 16 13 19 13 20 19 x3 24 18 20 19 22 21 x4 19 20 16 25 x5 23 26 26 24 28 23 23 Test at a = 0.01 to determine if the population means are all the same. 1. The null hypothesis is Ho: Oui = 2 = 43 Oui = ly = H3 = 44 OM = H2 = H3 = HA = Hs 2. This is a...
Consider the following hypothesis test. a. What is your conclusion if n 1-21, s 1 2-87, n 2 26, and s 2 2 4? Use α-05 and the p-value approach. Calculate the value of the test statistic (to 2 decimals). 2.05 3 The p-value is between .02 and.05 What is your conclusion? Cannot conclude that the two population variances are different b. Repeat the test using the critical value approach. What is the rejection rule for this hypothesis test? Round...
section 9.5
A sample mean, sample size, and sample standard deviation are provided below. Use the one-mean t-test to perform the required hypothesis test at the 5% significance level x = 23, s = 6, n = 32, Ho H = 27, H.: H = 27 Click here to view a partial table of values of The test statistic ist=Q (Round to two decimal places as needed.) A sample mean, sample size, and sample standard deviation are provided below. Use...
Consider the following hypothesis test: Ho: u = 15 Hai ji #15 A sample of 50 provided a sample mean of 14.15. The population standard deviation is 4. Enter negative value as negative number. a. Compute the value of the test statistic (to 2 decimals). -.03 b. What is the p-value (to 4 decimals)? Use the value of the test statistic rounded to 2 decimal places in your calculations. c. Using a = 0.05, can it be concluded that the...
3-7
Consider the following hypothesis test: Ho: u=15 Ha: u15 A sample of 40 provided a sample mean of 14.16. The population standard deviation is 6. Enter negative value as negative number. a. Compute the value of the test statistic (to 2 decimals) b. What is the p-value (to 4 decimals)? Use the value of the test statistic rounded to 2 decimal places in your calculations. c. Using a 0.05, can it be concluded that the population mean is not...
x 1 11 20 16 19 15 16 10 x2 17 21 17 21 19 21 14 x3 19 22 21 22 24 23 X4 25 16 17 18 18 x5 26 18 18 22 21 Test at a = 0.10 to determine if the population means are all the same. 1. The null hypothesis is Ho: OM = M2 = M3 = Hy = 45 Oui = ly = H3 = 44 OH = H2 = 43 2. This...
A sample of 200 ROM computer chips was selected on each of 30 consecutive days, and the number of nonconforming chips on each day was as follows: 10, 21, 26, 18, 38, 20, 5, 23, 11, 22, 28, 12, 14, 22, 20, 19, 16, 25, 10, 17, 14, 17, 15, 22, 29, 15, 9, 19, 16, 25 Calculate pbar = LCL = UCL =
The following data represent the number of sweatshirts sold for each of the past six days for a department store. Day 2 4 Sales 12 8 4 14 Using an exponential smoothing technique with alpha equal to 0.4, what is the forecasting error for pay 4 OA. -4.6 O B. 6.0 C. OD. 8.8 The following data represent the number of complaints per month that customer service received at a large retailer over the last 15 months. Month Complaints 10...
ns Exercise 12.20 (Self-Test) Algorithmic Video The following data are believed to have come from a normal distribution. Use the goodness of fit test and α-,05 to testthis daim. Use Table 124. 17 23 22 23 19 23 18 21 19 13 11 20 18 19 21 20 18 14 23 23 22 42 29 27 26 30 27 33 23 28 Using six classes, calculate the value of the test statistic (to 2 decimals). 51.64 The p value is...