5. Test for convergence / divergence: (15 pts) 13n² – 2n+4 a) nº – n+3 n=1
Check convergence/divergence of series by applying appropriate test for convergence n Σ, (2n +1)3/2
Determine if the series convergence or divergence and state the test used: # 1.) sigma on top infinity when n=1 [(5/2n-1)] # 2.) sigma on top infinity when n=1 [(2 * 4 * 6 …2n/n!)]
Test the series for convergence or divergence clearly justify sin(2n) 1+21 n=1
Please show work. Thanks Determine the convergence or the divergence of the following series using any appropriate test from this chapter. BE SURE TO IDENTIFY THE TEST BEING USED!! 1. Σ 5(3)" 4" 230 n+1 4. in? + 2n +13n" n° +2° +5 3. =0 8n +80
For each of the following, use an appropriate comparison test to determine the convergence or divergence of the series. α) Σ 2n +17 22 In n +5 α) Σ 2n +17 22 In n +5
Test the series for convergence or divergence. 00 (-1)" +1 2n? n = 1 converges diverges If the series is convergent, use the Alternating Series Estimation Theorem to determine how many terms we need to add in order to find the sum with an error less than 0.00005. (If the quantity diverges, enter DIVERGES.) terms Need Help? Read It Watch It Talk to a Tutor Submit Answer Viewing Saved Work Revert to Last Response
2. Test the Series for convergence or divergence. In(n) Σ(-) Σ- 4 n=3 η=1 n 3. Determine which option is absolutely converges and explain in details the reason. 1 (=Σ(-1)" 3 =Σ(-1)" C-Σ(-1)* tan(n) η Υ -Σ-1): E = None of these n!
5) Test the series for convergence or divergence. n a) In 3n +1 n= b) cos(3n) 1+ (1.2)" n=1
15. -74 POINTS SCALC8 11.7.508.XP. Test the series for convergence or divergence. 06 + 1 n = 1 n° +1 convergent divergent
Test for convergence or divergence of the series and identify the test used. In(n) n n = 2 O diverges by the Direct Comparison Test O converges by the Direct Comparison Test O converges by the p-Series Test O diverges by the p-Series Test Determine the convergence or divergence of the series. (If you need to use co or -, enter INFINITY or -INFINITY, respectively.) 00 į (-1)"(4n – 1) 3n + 1 n = 1 4n - 1 lim...