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Superman It is well known that bullets and other missiles fired at Superman simply bounce off...

Superman It is well known that bullets and other missiles fired at Superman simply bounce off his chest (Fig.7-22). Suppose that a gangster sprays Superman's chest with 9 g bullets at the rate of 105 bullets/min, the speed of each bullet being 400 m/s. Suppose too that the bullets rebound straight back with no change in speed. What is the magnitude of the average force on Superman's chest from the stream of bullets?

____N?     PLEASE SHOW ME THE WORK SO i CAN LEARN ON HOW TO DUE SUCH A PROBLEM. THANKS

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Answer #1
in 1 minutes there are 105 bullets.
so conseration of momentum
P=2*105*m*v
where P be change in momentum of the bullets. Also the pulse that exerted by the bullets to super man.
we have
P=F*t (pulse)
so F=P/t=2*105*m*v/60=12.6(N)
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Answer #2

mass of the each bullet m =9 g =9*10^-3 kg
speed of the each bullet v =400 m/s
rate of flow of bullets (n/dt)=105 bullets/min =105/60 s =1.75 bull/s
force F =dP/dt ........ (1)
cange in momentum dP =mv-(-mv) =2mv
for n particles ,dP =2nmv ...... (2)
force F =2nmv/dt =2mv(n/dt)
substitute the given data in above equation we get
force F =12.6 N

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