It is well known that bullets and other missiles fired at
Superman simply bounce off his chest. Suppose that a gangster
sprays Superman's chest with 7 g bullets at the rate of 105
bullets/min, the speed of each bullet being 450 m/s. Suppose too
that the bullets rebound straight back with no change in speed.
What is the magnitude of the average force on Superman's chest from
the stream of bullets?
N
Average Force on the chest = rate of change of momentum (p)
initial velocity of bullet = 450 m/s
Initial momentum = 450 × 7*10^-3
Final velocity = - 450 m/s
Final momentum = -450 ×7*10^-3
Force exerted by each bullet = 7*10^-3 (450 - (-450))
= 6.3 N
Number of bullet hitting per second = 105/60 = 1.75
Average force = 6.3 × 1.75 = 11 N
It is well known that bullets and other missiles fired at Superman simply bounce off his...
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