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Question 2: Use Ampere's Law to find the magnetic field in the interior of a toroidal...
Using Ampere's Law, find the magnetic field in all space produced by: a) A solid conducting...
Using Ampere's Law, find the magnetic field in all space produced by: a) A solid conducting cylinder carrying a total current I. b) Two cylindrical conductings opposite currents (each equal to I in magnitude). The inner one has radius a, the outer one b. c) A solenoid with N turns and length L carrying current I in each turn (inside only, far from the ends). d) A toroidal solenoid with N turns, inner radius a, outer radius b. e) An...
3. Starting with Ampere's law, find the magnetic field at r from the axis, inside and...
3. Starting with Ampere's law, find the magnetic field at r from the axis, inside and outside of a circular toroid, figure below, of major radius R and minor radius a, wrapped with N turns of wire carrying current I. Evaluate for r=R=5cm, a=2cm,N=1000,1=3A
3 The magnetic field inside a toroidal solenoid is not uniform as for the long, straight...
3 The magnetic field inside a toroidal solenoid is not uniform as for the long, straight solenoid. Over the cross-sectional area of the toroid the magnetic field is stronger near the inner HoNI radius of the torus and somewhat weaker near the outer radius according to B(r) 2Tr So we cannot technically use the simple expression P2 = BAfor the flux through one turn of wire. Nevertheless, the textbook uses an approximate constant value for an equivalent uniform magnetic field...
Chapter 28 - Sources of Magnetic Field: Current-carrying Wires, Ampere's Law, Biot-Savart Law, Ferromagnetism, Solenoids, and...
Chapter 28 - Sources of Magnetic Field: Current-carrying Wires, Ampere's Law, Biot-Savart Law, Ferromagnetism, Solenoids, and Tore roblem 28.29 A 170 m-long copper wire, 2.40 mm in diameter including insulation is tightly wrapped in a single layer with adjacent coils touching, to form a solenoid of diameter 2.50 cm (outer edge). Part A What is the length of the solenoid? 90 AED - O ? Submit Request Answer Part B What is the field at the center when the current...
The magnetic field inside a toroidal solenoid is discussed in Example 28.11 of the text book. There the thickness of th...
The magnetic field inside a toroidal solenoid is discussed in Example 28.11 of the text book. There the thickness of the solenoid and variation of the magnetic field across the cross section were ignored. Let's include these effects into consideration. The solenoid in the figure has a rectangular cross section. It has N uniformly spaced turns, with air inside. The magnetic field at a point inside the toroid was derived in Example 28.11. Do not assume the field to be...
(a) Use the Ampere's law to show that the strength of the magnetic field inside an...
(a) Use the Ampere's law to show that the strength of the magnetic field inside an ideal cylindrical solenoid (a coil) is given off by B = µ(0)ni where n is the revolution density (the number of revolutions per unit length of the solenoid) and i is the current through the solenoid. (3p) The current in the solenoid increases at a constant rate to a constant value I in a certain time t. (b) Draw a figure across the cross...
Problem 4: Consider a toroidal solenoid shown below. (a) Using Ampere's Law derive the equation for...
Problem 4: Consider a toroidal solenoid shown below. (a) Using Ampere's Law derive the equation for the magentic field inside the coil. (b) What number of turns will create a magnetic field of B 3.75.10 .T along a loop with radius 14.0.cm from the center of the coil. 12.0.cm s 15.0 cm 1.50-A
4. Toroidal solenoid #1 has mean radius r 1 - 40.0 cm, and cross-sectional area A1...
4. Toroidal solenoid #1 has mean radius r 1 - 40.0 cm, and cross-sectional area A1 - 16.0 cm? It is wound uniformly with N - 1000 turns of wire. Toroidal solenoid #2 has N2 = 100 turns of wire and is wound tightly around solenoid #1. If the current through the windings of toroidal solenoid #1 is changing at a rate of 1000 A/s, what is the emf induced in toroidal solenoid #2 (in mV)? (A) 43.5 (B) 60.0...
4. Toroidal solenoid #1 has mean radius r 1 = 40.0 cm, and cross-sectional area A1...
4. Toroidal solenoid #1 has mean radius r 1 = 40.0 cm, and cross-sectional area A1 = 16.0 cm2. It is wound uniformly with N1 = 1000 turns of wire. Toroidal solenoid #2 has N2 = 100 turns of wire and is wound tightly around solenoid #1. If the current through the windings of toroidal solenoid #1 is changing at a rate of 1000 A/s, what is the emf induced in toroidal solenoid #2 in mV)?
Using Ampere's Law, find the magnetic field in all space produced by: a) A solid conducting cylinder carrying a total current I. b) Two cylindrical conductings opposite currents (each equal to I in magnitude). The inner one has radius a, the outer one b. c) A solenoid with N turns and length L carrying current I in each turn (inside only, far from the ends). d) A toroidal solenoid with N turns, inner radius a, outer radius b. e) An...
3. Starting with Ampere's law, find the magnetic field at r from the axis, inside and outside of a circular toroid, figure below, of major radius R and minor radius a, wrapped with N turns of wire carrying current I. Evaluate for r=R=5cm, a=2cm,N=1000,1=3A
3 The magnetic field inside a toroidal solenoid is not uniform as for the long, straight solenoid. Over the cross-sectional area of the toroid the magnetic field is stronger near the inner HoNI radius of the torus and somewhat weaker near the outer radius according to B(r) 2Tr So we cannot technically use the simple expression P2 = BAfor the flux through one turn of wire. Nevertheless, the textbook uses an approximate constant value for an equivalent uniform magnetic field...
Chapter 28 - Sources of Magnetic Field: Current-carrying Wires, Ampere's Law, Biot-Savart Law, Ferromagnetism, Solenoids, and Tore roblem 28.29 A 170 m-long copper wire, 2.40 mm in diameter including insulation is tightly wrapped in a single layer with adjacent coils touching, to form a solenoid of diameter 2.50 cm (outer edge). Part A What is the length of the solenoid? 90 AED - O ? Submit Request Answer Part B What is the field at the center when the current...
The magnetic field inside a toroidal solenoid is discussed in Example 28.11 of the text book. There the thickness of the solenoid and variation of the magnetic field across the cross section were ignored. Let's include these effects into consideration. The solenoid in the figure has a rectangular cross section. It has N uniformly spaced turns, with air inside. The magnetic field at a point inside the toroid was derived in Example 28.11. Do not assume the field to be...
Problem 4: Consider a toroidal solenoid shown below. (a) Using Ampere's Law derive the equation for the magentic field inside the coil. (b) What number of turns will create a magnetic field of B 3.75.10 .T along a loop with radius 14.0.cm from the center of the coil. 12.0.cm s 15.0 cm 1.50-A
4. Toroidal solenoid #1 has mean radius r 1 - 40.0 cm, and cross-sectional area A1 - 16.0 cm? It is wound uniformly with N - 1000 turns of wire. Toroidal solenoid #2 has N2 = 100 turns of wire and is wound tightly around solenoid #1. If the current through the windings of toroidal solenoid #1 is changing at a rate of 1000 A/s, what is the emf induced in toroidal solenoid #2 (in mV)? (A) 43.5 (B) 60.0...
4. Toroidal solenoid #1 has mean radius r 1 = 40.0 cm, and cross-sectional area A1 = 16.0 cm2. It is wound uniformly with N1 = 1000 turns of wire. Toroidal solenoid #2 has N2 = 100 turns of wire and is wound tightly around solenoid #1. If the current through the windings of toroidal solenoid #1 is changing at a rate of 1000 A/s, what is the emf induced in toroidal solenoid #2 in mV)?
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