Question

Ez12/2 zbom / 3.3 A pair of parallel plates are connected to a 12-V battery and separated by 20 cm The area of the plate is 4,0 m, () Find out the energy stored in this capacitor. Answer: 1.27 x 10JI (b) If The capacitor is still connected with the battery and the separation of two plates is doubled, what happens to the stored energy? (ey if the capacitor is disconnected from the battery and then the separation of two plate is doubled, what happens to the stored energy?

Answer 1

& Answer (a) ginen Area of the plates of a parallel plate capa A = 4m2 Distance between the two plates d = 20cm=0.2m potential difference across the plate v= 12 v Capacitance of the capacitor is given by the relation ceboll Electrostatic energy stored in the capacitor is given by the relation 62% cu2 where, - 604 v2 Co a permittivity of free space =18.85 *182c2nim2 8.85x10''* 4 x(2) 2 -8 . -1:27 X10 J -12 0.2

seperation between the two plate is doubled then energy stored in the capacitor given d = 2*0.2m 2 0.4m. Now & Bg A 02 atx 8.85x1024 XQ22 2^ oit . = 6 312