Solve the following differential equation using variation of parameters. d yt) 2 dy() +7- + 10y() u(t) dt dt2 y(0) 0, y'(0) = 3 d yt) 2 dy() +7- + 10y() u(t) dt dt2 y(0) 0, y'(0) = 3
please solve with mathlab and post screenshots of the code 10.y" + 2y' +10y -6e sin(3t),y(0) 0,y'(0) 1 10.y" + 2y' +10y -6e sin(3t),y(0) 0,y'(0) 1
Find a general solution to the given Cauchy-Euler equation for t> 0. 2d²y dy +41 - 10y = 0 dt at² The general solution is y(t) =
(1 point) Find y as a function of x if y" – 7y" + 10y' = 12et, y(0) = 10, y(0) = 29, y' (0) = 10. y(x) = (21/2)+(41/2)^(2x)-3e^(5x)+3e^(x) 000 (1 point) Find a particular solution to y" + 36y = –24 sin(6t). yp = 16-3e^(-3t)-8cos(3t)
Find the solution of the initial value problem y′′+7y′+10y=0, y(0)=11 and y′(0)=−46.
Solve the given initial value problem. y" +10y' +25y = 0; y(0) = 3, y0) = -10
find y(t) solution of the initial value problem y’’-10y’+21y=2u(t-3), y(0)=0,y’(0)=0 here u(t) denotes the step function
In Problems 1 through 10, find a function y = f(x) satisfy. ing the given differential equation and the prescribed initial condition. 1.dy = 2x + 1;y(0) = 3 In Problems 1 through 10, find a function y = f(x) satisfy. ing the given differential equation and the prescribed initial condition. 1.dy = 2x + 1;y(0) = 3
Find the solution to the initial value problem: dy dy/dx=x^ 2√1 + x^3/1+cos y y(0)=2 the 1+x^3 is all in square root.
(1 point) Find y as a function of x if y(4) – 10y" + 254" = -392e-27, = 16. y(0) = 4, y(0) = 24, y" (O) = 17, y" (0) y(x) =