Homework Answers
Flux equal to net charged enclosed in the gaussian surface
If gaussian surface is increased
Charge remains unchanged
Then final flux is similar as initial
Hence option b is correct
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2 There is a certain net flux ®; through a Gaussian sphere of radius r enclosing...
A charged particle is held at the center of two concentric conducting spherical shells. Figure (a) shows a cross section. Figure (b) gives the net flux Φ through a Gaussian sphere centered on the particle
A charged particle is held at the center of two concentric conducting spherical shells. Figure (a) shows a cross section. Figure (b) gives the net flux Φ through a Gaussian sphere centered on the particle, as a function of the radius r of the sphere. The scale of the vertical axis is set by Φs = 5.5 × 105 N·m2/c. what are (a) the charge of the central particle and the net charges of (b) shell A and (c) shell...
Charge Q is spread uniformly throughout the volume of a sphere of radius R. The flux...
Charge Q is spread uniformly throughout the volume of a sphere of radius R. The flux through a spherical Gaussian surface of radius r < R (concentric with the sphere of charge) in equal to a) Q/element of_0 b) Qr/element of_0 R c) Qr^2/element of_0 R^2 d) Qr^3/element of_0 R^3
(a) Imagine a gaussian sphere of radius R with an electron at the center. Write down...
(a) Imagine a gaussian sphere of radius R with an electron at the center. Write down the total flux through the sphere (including the sign) in terms of physical constants and R. (b) Suppose we place a proton a distance 2R from the electron. What is the flux through the original gaussian sphere? (c) How do your answers to parts (a) and (b) change if we replace the gaussian sphere with a cube of width 2R? (d) How do your...
3) A Gaussian sphere of radius r is centered at the origin. A point charge q...
3) A Gaussian sphere of radius r is centered at the origin. A point charge q is within the sphere, but not at the origin. The electric flux through the sphere equals (A) zero (O)méai (D) mCra
#8 Gauss's Law and The Shell Theorem Consider a hollow sphere with charge uni- formly distributed...
#8 Gauss's Law and The Shell Theorem Consider a hollow sphere with charge uni- formly distributed on its surface. Suppose the total charge is Q, where Q may be positive or negative Recall that Gauss's law as we have seen it is: Qenclosed ΣΕ A = EO where A = 47tr2 is the total area of the Gaussian surface Suppose the sphere radius is Ro and r > Ro. In terms of Gauss's Law, the reason why the electric field...
18a) Find the flux through the whole surface of the sphere. b) Find the magnitude and...
18a) Find the flux through the whole surface of the sphere. b) Find the magnitude and direction of E at the surface.1 Now put the same charge at the center of a spherical shell- with twice the diameter. c) Find the magnityde and direction of E at the surface.1 d) Find the flux through the whole surface of the sphere.1 e) Why is the flux the same, even though E is weaker?1 18, A particle with charge of 12.0 μC...
14) After further bombardment of the copper sphere (radius 1.2cm, surface area 18cm?, volume 7.2cm), the...
14) After further bombardment of the copper sphere (radius 1.2cm, surface area 18cm?, volume 7.2cm), the total charge increases to +820 nC total. How much electric flux passes through a Gaussian sphere that's a tiny bit larger than the copper sphere, and completely contains the copper sphere?
A solid conducting sphere has a radius of 10.7 cm and a net electrical charge of...
A solid conducting sphere has a radius of 10.7 cm and a net electrical charge of 4.06 nC. What is the magnitude of the electric field at a distance 18.6 cm from the sphere's center? Select one a. 10.5 N/C b. 1.9664 N/C c. 1050 N/C d. 196 N/G e. 3190 N/C 2. A hollow conducting sphere has an inner radius of 5.38 cm and an outer radius of 8.637 cm. The sphere has a net electric charge of -6.87...
3. If the net flux through a closed Gaussian surface is zero, all of the following...
3. If the net flux through a closed Gaussian surface is zero, all of the following statements might be true. Which two statements must be true? a. There are no charges inside the surface. b. The net charge inside the surface is zero. c. The electric field is zero everywhere on the surface. d. The number of field lines entering the surface equals the number of field lines eaving the surface.
Four equal charges are located at the corners of a square of side d. If the...
Four equal charges are located at the corners of a square of side d. If the magnitude of each charge is doubled, then what happens to the resultant force on each charge? It is doubled. It is quadrupled. It increases by a factor of 8. It remains the same. None Of the other choices is correct. A particle travelling along the +x-axis enters an electric field directed vertically upward along the +y-axis. If the particle experiences a force downward because...
Charge Q is spread uniformly throughout the volume of a sphere of radius R. The flux through a spherical Gaussian surface of radius r < R (concentric with the sphere of charge) in equal to a) Q/element of_0 b) Qr/element of_0 R c) Qr^2/element of_0 R^2 d) Qr^3/element of_0 R^3
3) A Gaussian sphere of radius r is centered at the origin. A point charge q is within the sphere, but not at the origin. The electric flux through the sphere equals (A) zero (O)méai (D) mCra
#8 Gauss's Law and The Shell Theorem Consider a hollow sphere with charge uni- formly distributed on its surface. Suppose the total charge is Q, where Q may be positive or negative Recall that Gauss's law as we have seen it is: Qenclosed ΣΕ A = EO where A = 47tr2 is the total area of the Gaussian surface Suppose the sphere radius is Ro and r > Ro. In terms of Gauss's Law, the reason why the electric field...
18a) Find the flux through the whole surface of the sphere. b) Find the magnitude and direction of E at the surface.1 Now put the same charge at the center of a spherical shell- with twice the diameter. c) Find the magnityde and direction of E at the surface.1 d) Find the flux through the whole surface of the sphere.1 e) Why is the flux the same, even though E is weaker?1 18, A particle with charge of 12.0 μC...
14) After further bombardment of the copper sphere (radius 1.2cm, surface area 18cm?, volume 7.2cm), the total charge increases to +820 nC total. How much electric flux passes through a Gaussian sphere that's a tiny bit larger than the copper sphere, and completely contains the copper sphere?
A solid conducting sphere has a radius of 10.7 cm and a net electrical charge of 4.06 nC. What is the magnitude of the electric field at a distance 18.6 cm from the sphere's center? Select one a. 10.5 N/C b. 1.9664 N/C c. 1050 N/C d. 196 N/G e. 3190 N/C 2. A hollow conducting sphere has an inner radius of 5.38 cm and an outer radius of 8.637 cm. The sphere has a net electric charge of -6.87...
3. If the net flux through a closed Gaussian surface is zero, all of the following statements might be true. Which two statements must be true? a. There are no charges inside the surface. b. The net charge inside the surface is zero. c. The electric field is zero everywhere on the surface. d. The number of field lines entering the surface equals the number of field lines eaving the surface.
Four equal charges are located at the corners of a square of side d. If the magnitude of each charge is doubled, then what happens to the resultant force on each charge? It is doubled. It is quadrupled. It increases by a factor of 8. It remains the same. None Of the other choices is correct. A particle travelling along the +x-axis enters an electric field directed vertically upward along the +y-axis. If the particle experiences a force downward because...
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