Question

MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK NEXT Chapter 27, Problem 041 In the figure E: - 4.20 V, E2 = 1.01 V, R = 4.959, R2 - 1.549, R3 - 5.03 , and both batteries are ideal. What is the rate at which energy is dissipated in (a), (b) Ry and (c) Ry? What is the power of (d) battery 1 and (e) battery 2? M 3R (a) Number (b) Number (c) Number Units Units (d) Number Units (e) Number Units Click if you would like to Show Work for this question: Open Show Work

Answer 1

To SOLUTION:- Ri lio iz Rz tie Bez E, IT In this circuit diagram, At function o, istis- iz (using Kircheff's current law) Now, lu loopt, using kirchoff Sveltage law, & +R, 6, + R₂ 13=0 & t Riis + R3(4,+12) = 0 4.20+4.951, +5.03(1,ti2)=0 9.981; +5103 iz = -4.20 -O Now, wing loup 2, using Kirchiff's Voltage law, Eq + R₂ iz + R313=0 Ez+ Reiz + R3(1,+12)=0 1.01 +1.54i2 +5.03(+12)=0 5.03i+6.57iq = -1.01 — ☺ from (1) and (2), 1=-0.5591 A, iz = 0.2743 A (2) The rate at which Energy is dissipated in Rig &, = ij?R, = (-0.5591**(4.95) = 1.54733 Walt

(6) Energy Rate in R2, = iz R2 = (0.2743)** 1.54 = 0.11587 watt (C) Energy Rate in R3, E = i? R3 = iz? (Ry) = (1, +iz] R3 = (-0.5591+0.2743)345103 = 0.40798 Watt (d) Power of Battery 1, P, = {,i 514.20)(-0.5591) =-2.34822 Watt for Power TP, = 2.34822 watt (e) Power of Battery 2, P2 = Eziz =(1.01) (0.2743) = 0.27704 Walt