Question

rading Time Dav Experiment#7: Electrochemical Cells Part II. Cu Concentration Cell [Cu2+] of the stock solution: 02 Potential difference for various concentration cells. (- ) 0.5 M 0.05 M 0.005 M 0.0005 M 0.5 M 045 . O 88 0.05 M .0252 0.005 M 0.0005 M Concentration Difference Concentration Ratio Log(Conc. Ratio)Measured Potential 0.5 M/0.05 M 0.5 M/0.005 M 0.5 M/0.0005 M Attach 3 graphs: (1.) Ecell vs. Concentration Difference; (2) Ecell vs. Concentration Ratio; (3) Ecell vs. log(Conc. Ratio)
0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
rading Time Dav Experiment#7: Electrochemical Cells Part II. Cu" Concentration Cell [Cu2+] of the stock solution:...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Post-Laboratory Report (Page 1/1) Group Number Date: Day Time 1. The salt bridge in Goal #1 was s...

    Post-Laboratory Report (Page 1/1) Group Number Date: Day Time 1. The salt bridge in Goal #1 was soaked with a saturated ammonium nitrate solution. In which direction do the ammonium ions move when this salt bridge completed the electric circuit? Toward the zinc metal or toward the copper metal? In which direction do the nitrate ions move? 2. In a concentration cell, what would be the potential if we studied two solutions that had the same concentration? Show that the...

  • Prelab Activity: Electrochemical Cells To determine the solubility product of copper(II) carbonate, CuCO3 , a concentration...

    Prelab Activity: Electrochemical Cells To determine the solubility product of copper(II) carbonate, CuCO3 , a concentration cell as described on pages 71-72 of the lab handout is constructed. The temperature of the Galvanic cell is measured to be 22.5°C, and the cell potential 282 mV (0.282 V). Using this data and Equation 8 in the lab manual, calculate the Ksp for CuCO3 and report your answer with three significant digits. For the Galvanic cell you will construct in PART B,...

  • Partner's Name Instructor Procedure I, Voltaic Cell Zn/Zn2+ 1.0 M || Cu2+ 1.0 M/Cu In the...

    Partner's Name Instructor Procedure I, Voltaic Cell Zn/Zn2+ 1.0 M || Cu2+ 1.0 M/Cu In the space below write the equations for the two half reactions and sum them appropriately to calculate the standard reaction potential for a 1.0 M voltaic cell. Show the overall net ionic equation for this reaction. 9pts.) Standard reaction potential Write the expression for Q for this redox reaction. (4 pes) In the space below show a calculation using the Nemst equation to determine the...

  • need help with the rest of the table EXPERIMENT 10 DETERMINATION OF THE ELECTROCHEMICAL SERIES PURPOSE...

    need help with the rest of the table EXPERIMENT 10 DETERMINATION OF THE ELECTROCHEMICAL SERIES PURPOSE To determine the standard cell potential values of several electrochemical coll INTRODUCTION The basis for an electrochemical cell is an oxidation reduction Corredor be divided into two half reactions reaction. This reaction can Oxidation half reaction Gloss of electrons) takes place at the anode, which is the positive electrode that the anions migrate to Chence the name anode) Reduction half reaction (gain of electrons)...

  • 5. What was the purpose of the NaNO3 solution in this experiment? 6. Could a solution...

    5. What was the purpose of the NaNO3 solution in this experiment? 6. Could a solution of NaCl be used instead of NaNO3? 7. What was the purpose of FeSO4 solution in this experiment? 8. Could a solution of FeCl, be used instead of FeSO4? 9. Could a solution of NaSO4 be used instead of FeSO4? 10. Calculate the standard cell potential for the spontaneous redox reaction between a Pb(s)/Pb(NO3)2(aq) half-cell and a Ag(s)/AgNO3(aq) half-cell. Which metal would be oxidized?...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT