Question

9. FALLING LOOP A rectangular loop is w in width and very long in height. It is held vertical, initially at rest. The loop has internal resistance R. It is in a region of space where there is a uniform magnetic field of strength Bo which is perpendicular to the plane of the loop. The region of space directly below the loop has no magnetic field in it. When the loop is dropped the magnetic flux will change and the loop will experience an induced EMF, and an induced current. a) Obtain an expression for the vertical force on the top edge as a result of the induced current and the externally applied field. b) Use Newton's laws to obtain an expression for the vertical position of the loop as a function of time.

Answer 1

Answer:

Answer: Given that A rectanglar Loop is w in width and very long in height. Set the magnetic field is vertically downwards pager. In magnetic field, suppose ! x is height of loop inclued into magnetic field. into the :. Area in the magnetic field at any Paper instaneous time t is A = Wx. (w.) width , x-> height) from paradays principle, EMF will produce due to change in magnetic flux. (O - BA) .. E= -BdA E = - Bw (dx)

let d e velocity of loop u de : EMF E= -Bwv Current (I) = EME -BWF R Induced current I= - Buy . BUV Force on a loop is F= I (TXB) F . I LB Sino F = IBX sino=1 0-90 2= x R 6. Newton's law F = mg mg. Bove x - x ma l Xc