Question

A closed loop conductor that forms a circle with a radius of 2m is located in a uniform but changing magnetic field. If the maximum emf induced in the loop is 5V what is the maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies?

Draw a sketch or circuit diagram. • Indicate the direction of the applied magnetic field • Is the flux increasing, decreasing or staying the same? • Use Lenz’s law to determine the direction of the induced current. • List known and unknown values

Start with the expression for Faraday’s law • Determine an expression for the flux as a function of time • Substitute in the known values • Solve for the desired unknown • Check units and assess if your answer is reasonable

Answer 1

* Answer Here, we given with A closed loop conductor that forms a cirure with a radies of am is located miradius cola 2m Maximum induced emf = it is oriented perpendicular tu lood Peane. sv, field, Sketch - in our diagram magnetic field is in Positive x direction, → Here, the change of magnetic field is at maximum indriced emf so, flux is decreasing with in the loop. In our diagram, when this bar magnet is thrust in to the coil, the strength of magnetic field increases in the coil (loop). The current remf) induced will Oppose the motion of bar magnet it means the direction of current will be

in opposite direction by which that is (current) inaused. - so we can say that indriced current in LOOP is counter clock wise (from diagram) → This is the Lentz's law aspect for at given situation, e Emf) - we can It → Here, we have E vane N (Number of tron) which is one; AB Cchanging in magnetic (field), radius of loop (8), so, from that able to find, Area ,CA.2722) For given problem Let's starting with Faraday's law of induction states that, the emf induced by a change in magnetic flux, emf Conduced) - At (negetive sign) This shows lenz's car. When flux changes by so in a time at Change in feux .oo filux is given by A ACB.AAC8A LOS) for perpendicular 0 - 0° jܐ

.: AP ACBA) se At SB. A [Area is not changing with time) Az Let's substitute the know values for Emf · NA (BA) At Here, we have N21 A 2 7772 .A - TT (2)² 'n A -40 m m2 and Emf zov. , 5: -M) AB (407) at ll 0.398089 Cor) sBis 5 (v) 4 17 ime st also, we have lune Ils ) (Tesia) ДВ 2 0.398089 TIS st .: Chang in field per sec. is about AB 0.40 TIS At