If a test statistic in one tailed test is 1.23 and the critical value is 1.645, there is No sufficient evidence in the favour of alternative hypothesis.
This is because we accept null hypothesis as test statistic value is less than critical value.
QUESTION 52 Term 19: If a test staistic in a one-tailed test is 1.23 and the...
Question Hello The test statistic in a two-tailed testis 2 2.51. Determine the value and decide whether at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis Click here to view a partial table of areas under the standard normal curve The P-value is (Round to four decimal places as needed) This Pavalue sufficient evidence to reject the null hypothesis in favor of the alterative hypothesis because it is...
The test statistic in a two-tailed test is z=0.34 Determine the P-value and decide whether, at the 10% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. LOADING... Click here to view a partial table of areas under the standard normal curve. The P-value is nothing. (Round to four decimal places as needed.) This P-value ▼ sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis because it...
The value obtained for the test statistic, z, in a one-mean 2-test is given. Whether the test is two tailed, left tailed, or right tailed is also specified. For parts (a) and (b). determine the P-value and decide whether, at the 1% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. a. The test statistic in a two-tailed test is z= -1.42. The P-value is (Round to three cocimal places as...
The test statistic in a two dash tailedtwo-tailed test is zequals=1.79 Determine the P-value and decide whether, at the 10% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. LOADING... Click here to view a partial table of areas under the standard normal curve. The P-value is (Round to four decimal places as needed.) This P-value sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis because it...
The test statistic in a two dash tailed test is z= -2.84. Determine the P-value and decide whether, at the 1% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. *Please show me a way to do it on the calculator (ti-84)*
The test statistic in a left-tailed test is z= - 1.33. Determine the P-value and decide whether, at the 10% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. BE! Click here to view a partial table of areas under the standard normal curve. The P-value is .
This Question: 1 pt 4 of 19 (1 complete) The test statistic of 2.21 is obtained when testing the daim that p>0.7 a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed b. Find the P-value. c. Using a significance level of x=0.10, should we reject He or should we fail to reject Ha? Click here to view page 1 of the standard normal distribution table Click here to view page 2 of the standard normal distribution table. a....
Question 8 3 pts The a two-tailed hypothesis test Is related to a confidence interval at the same level of alpha. All of the answers are true. Is expressed in a probability framework with a chance of being wrong in our conclusion. Has an alternative hypothesis that uses Not Equal in the expression For this problem you will need a t-table. What is the t-value needed for the critical value for a one-tailed upper hypothesis test with a sample size...
QUESTION 4 Use the one- proportion z-test to perform the specified hypothesis test. Use the criticalvalue approach x®7, n.81 , H 0: p-0.08, H a: p # 0.08, α-0.10 O z = 0.21; critical values 1.645; do not reject Ho o z-1.87; critical values +1.645; reject Ho O z -0.41; critical values ±1.28; do not reject Ho O z. 0.21; critical values 1.28; do not reject Ho perform the specified hypothesis test. Use the critical-value approach
QUESTION 4 Use the...
Read the z statistic from the normal distribution table and circle the correct answer. A one-tailed test (upper tail) at a 123 level of significance, a. 1.645 b. 1.54 C. 1.96 O d. 1.16 When the hypotheses Ho μ z 100 and Ha μ < 100 are being tested at a level of significance of o, the null hypothesis will be rejected if the test statistic z is a. -za O c. 100 For a one-tailed test (upper tail) with...