Question

reactive power from 10d= 33.5VAR

(2-1) 1201 20° 60 Hz (100+j50) 11. Assume the reactive power calculated in part d of problem 10 is added in parallel to the load impedance as shown here. You can assume VAN won't change significantly by doing this (that is, we'll live with whatever error we get by keeping VAN the same as in problem 10). Determine the reactance X that needs to be added and the amount of capacitance or inductance this represents (as the case may

-33.5VA

Answer 1

V Roactivo powon paTalDe voliageo sama By voltago division rulo Vz3 (100tj so) jx=z00 Vc = 120L0 xzoa 2010 20+ 2-11 20(00t/50) -(00tjco)xjx o0t/(5ox) g0isox) Zo=100jXo-50xo 100 t(50tx) V 12010/ 100 j xoy -5ox 100+jsotx) 00jYooro t(2-j1) l00tj50+x) 0" 20ו( toט)xaq - s0xog) toojxay -5o xot (2-j1) (100(sorxou) 120 (oL(00 04-50 xO (950-49x0u) +10 j xaq 120 (00xa4 0raa) Seso-49ra)(02 ou) 120 X120 Looxaa)50 vou 250-4910a)t (102xau) |Vx) 2 2 Vx)2 = 33,5 I vx) 33 5 xo 12oifoo 33:5 [As0-4x)(03re

p0)10000X+2500x =33.5(6D500+2401 24500x0q 2 120) 12 500 x0a J 33 5 62500 12805 xo -24500 1X103 xay 2 64 Or42X106x 6 180 XI0X .82X106 X0a 10 2 2 82xQq = 2 + O142 Xo 180 xo 2 -2 =0 179.58 XQa O82 x0 O182 1(180)2+4(180)x2 179,58180 2 X180 O.82+ 18 3,95 360 Yoq Roactitan is no Ragative -0.22 t18395 360 Yoq Or5 2 11