What is substrate concentration, expressed as a multiple of Km, when an enzyme reaction is observed...

Question

Question

What is substrate concentration, expressed as a multiple of Km, when an enzyme reaction is observed to have an initial rate V

Answer 1

Answer #1

Answer is 3 Km

Vo = max [s] Km+[s] Vo = 0o 75 Vmax 0.75 Vmax = Vmax [s] Km+[s [s] 0.75 Vmax Vmax km +[s] 0.75 (km+s] - [s] 0.75 km =[s] - •7

Answer 2

Similar Homework Help Questions

5. The Km of an enzyme of an enzyme-catalyzed reaction is 6.5 uM. What substrate concentration...

5. The Km of an enzyme of an enzyme-catalyzed reaction is 6.5 uM. What substrate concentration will be required to obtain 55% of Vmax for this enzyme? (10 pts)
For an enzyme that follows the Michaelis-Menten kinetic, what substrate concentrations (relative to Km) are needed...

For an enzyme that follows the Michaelis-Menten kinetic, what substrate concentrations (relative to Km) are needed for the speed of the reaction to be 0.12 there vmax 0.25 there vmax 0.5 there vmax 0.9 there vmax.
The key factor that controls the initial rate of an enzyme catalysed reaction (Vo) is the...

The key factor that controls the initial rate of an enzyme catalysed reaction (Vo) is the concentration of the substrate of the reaction ([S]). In Damon's Michaelis-Menten experiment, the highest concentration of substrate used was 500 UM. What do you think will happen to the reaction velocity if higher concentrations of substrate were used? Select one: a. Vo will reach a plateau at higher (S) values O b. Vo will increase exponentially as (S) is increased O c. Vo will...

An enzyme catalyzes a reaction with a Km of 8.50 mM and a Vmax of 2.70...

An enzyme catalyzes a reaction with a Km of 8.50 mM and a Vmax of 2.70 mM 5-1. Calculate the reaction velocity, vo, for each substrate concentration. [S] = 2.25 mM Vo: 0.5 mM.s-1 [S] = 8.50 mM 1.70 mMs-1 [S] = 13.0 mM [S] = 13.0 mM Vo: 2.05 mm. s-1
If the enzyme concentration is 3.8 X 10-8, what concentration of substrate would generate a velocity...

If the enzyme concentration is 3.8 X 10-8, what concentration of substrate would generate a velocity equal to 0.25 Vmax? Km is not needed. Km= 15.42M
Vmax of an enzyme-catalyzed reaction is A. the rate observed when the enzyme active sites are...

Vmax of an enzyme-catalyzed reaction is A. the rate observed when the enzyme active sites are saturated with substrate B. independent of the amount of enzyme present C. the rate observed at the highest substrate concentration that can be experimentally obtained D. the initial rate observed at very low substrate concentrations

If the enzyme concentration is 3.8 X 10-8, what concentration of substrate would generate a velocity...

If the enzyme concentration is 3.8 X 10-8, what concentration of substrate would generate a velocity equal to 0.25 Vmax? Km is not needed.
6. An enzyme with a km of 0.06mmol/L hydrolyzed a substrate of a concentration 0.03 mmol/L....

6. An enzyme with a km of 0.06mmol/L hydrolyzed a substrate of a concentration 0.03 mmol/L. The initial velocity ws 0.0015 mmol/L.min!. Calculate the substrate concentration which gives an initial velocity of 0.003 mmol/L. min-1 7. Urease hydrolyzed urea at [s]=0.03mmol/L with a km of 0.06 mmol/L. The initial velocity observed was 1.5X10-3 mmol/L.min Calculate the initial velocity of the enzyme reaction when using [s]=0.12mmol/L
An enzyme catalyzes the reaction M N. The enzyme is present at a concentration of 3.5...

An enzyme catalyzes the reaction M N. The enzyme is present at a concentration of 3.5 nM, and the Vmax is 2.9 PM s-. The Km for substrate M is 6.5 MM. Calculate kcat kcat = 1 What values of Vmax and Km would be observed in the presence of sufficient amounts of an uncompetitive inhibitor to generate an a' of 1.3? apparent Vmax = UM S-1 apparent Km = UM

If the concentration of substrate in an enzymatic reaction is set to the Km of the...

If the concentration of substrate in an enzymatic reaction is set to the Km of the enzyme substrate system then the velocity is equal to: 0 units / second Vmax units/second Vmax/2 units/second 1/3 Vmax units/second 2/3 Vmax units/second 100 units / second