Question

Part B Classify the bonds formed between each pair of elements based on electronegativity values in the following table: 

Drag the appropriate items to their respective bins. 

Answer 1

Bond type. 1 1 s-0 Bond Electronegativity difference 1201 – 2.81 = H-p 0.7 Polar covalent 1 2.) - 2011 = Non polar covalent S- 12.5-2.51 = Non polar covalent 12.5 - 3.5 = Polar covalent Sc-0 1163-305 1 = 2.2 Tonic Be-f I los-4.0 1 = 205 Ionic Berce 1 1.5-3.0l = 105 Non polar covalent In general, I SEN is less than 0.5 then the bond is nonpoler covalent. G LEN is between 0.5 to lod, then the bond is considered polar covalent. GBEN G above lob, then it is considered lonic bond if metal is involved While if only non metals are involved, they are lonic above 2.0 only,