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Consider the following sample observations on stabilized viscosity of asphalt specimens. 2755 2892 3013 2857 2887 Suppose tha

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Answer #1

Average of the given sample = 2881, hence the requirement of average viscosity of 3000 does not appear to have been satisfied.

The hypotheses are:

H0: \mu = 3000

Ha: \mu != 3000

Test statistic, t = [ x̄ - μ ] / [ s / sqrt( n ) ], where x̄ is the sample mean, s is the sample std deviation and \mu is the hypothesized population mean.

=> t = (2881 - 3000) / (92.24 / sqrt(5)) = - 2.885

And, p-value = 0.0224

Since p-value < 0.05, we cannot reject the null hypothesis at the 5% significance level. Hence, there is sufficient evidence to conclude that the true viscosity differs from 3000. (Option b)

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