Suppose a sample of 1635 floppy disks is drawn. Of these disks, 228 were defective. Using the data, construct the 98% confidence interval for the population proportion of disks which are defective. Round your answers to three decimal places.
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p^ = x/n = 228/1635 = .13945
98% CI is given by a Z of 2.326
So, the 90% CI is given by
= p +/- Z*sqrt(p*p'/n)
= .13945 +/- 2.326*sqrt(.13945*.82055/1635)
= 0.120 to 0.159
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