Question

please explain

A Review | Constants | Periodic Table Percent ionization can be used to quantify the extent of ionization of an acid in solution and is defined by the following formula for the acid HA: A certain weak acid, HA, has a Ka value of 3.4x10-7. HA) ionized x 100% Percent ionization = - Part A Percent ionization increases with increasing Ka. Strong acids, for which Ka is very large, ionize completely (100%). For weak acids, the percent ionization changes with concentration. The more diluted the acid is, the greater percent ionization. Calculate the percent ionization of HA in a 0.10 M solution. Express your answer to two significant figures and include the appropriate units. View Available Hint(s) A convenient way to keep track of changing concentrations is through what is often called an I.C.E table, where I stands for "Initial Concentration," C stands for "Change." and E stands for "Equilibrium Concentration." To create such a table, write the concentrations of reactant(s) and product(s) across the top, creating the columns, and write the rows I.C.E on the left-hand side. Such a table is shown below for the reaction: A+B = AB C: Å N O 2 ? Value Units [A] [B] [AB] Submit Initial (M)

Answer 1

HO TAO I Initial HAL ool -a -2 O1-a Change +2 +x Equilibrium ka = [47] [4] ka= [ta) 0.1-7 ~ ool ou la Oil Ka = 2.2 34x107 = x x= 3.4x107xo.1 x= 3.48108 2= 3.4 x 168 = 0.000184 [#1] = 0.000184 % of ionization = 0.000184 -xlo Oil = 0.184 % n