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0.20 kg of air at pressure of 113 kPa occupies 0.18 m3 and from this condition...

0.20 kg of air at pressure of 113 kPa occupies 0.18 m3 and from this condition it is compressed to 1237 kPa accordingly to the law P*(V)1.28 = constant. Determine change of internal energy of the air in kJ,

Cp=1.005 kJ/kg K

Cv=0.718kJ/kg K

R=0.287 kJ/kg K

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o 18 m3 22 = 1227 kDa 1-28 1-28 1.28 v, 2 1237 と-R Cy 1237 y lo3 xe. C277-113x103 Ха.О,18 131: 13 Jou Teachers Signaiure.

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