1. The reaction below has the following rate law: rate 0.011 L/moles [SF]. ay iuns t...
2. At 500 °C, cyclopropane (C3H6) rearranges to propene (CH3CH=CH2): C3H6 (g) → CH3CH=CH2 (8) The reaction is first order and the rate constant is 6.7 x 10-4 5-1. (a) What is the rate law for the reaction, and; (b) if the initial concentration of C3H6 is 0.100 M, what is the concentration of cyclopropane of after 20 min?
1. Initial rate data at 25.0 °C are listed below for the reaction: 2 HgCl2 (aq) C2O (aq)2 C (aq)+ 2 CO:(g)+ Hg Cl(s) (COP)0 Expt. HgClalo Initial rate/ 3.1 x 10 1 0.100 0.20 1.2x 10 0.100 0.40 6.2x 10S 0.050 0.40 Use the data to determine the rate law for the reaction. 2. At 500 °C, cyclopropane (CsH6) rearranges to propene (CH3CH-CH2): CH CH=CH2 (g) CaHs (g) The reaction is first order and the rate constant is 6.7...
1. Initial rate data at 25.0 °C are listed below for the reaction: 2 HgCl2 (aq) + C,042 (aq) → 2 (aq) + 2 CO2(g) + HgCl(s) Expt. [HgCl2]0 [C:02) Initial rate/Ms? 0.100 0.20 0.100 0.40 3.1 x 105 1.2 x 104 6.2 x 10-5 0.050 0.40 Use the data to determine the rate law for the reaction. 2. At 500 °C, cyclopropane (C3H.) rearranges to propene (CH:CH-CH2): CH. (g) → CH,CH=CH2 (8) The reaction is first order and the...
A decomposition reaction has a half-life that is directly proportional to the initial concentration of the reactant. What is the order of the reaction? Geologists can estimate the age of rocks by their uranium-238 content. The uranium is incorporated in the rock as it hardens and then decays with first-order kinetics and a half-life of 4.5 billion years. A rock is found to contain 83.4% of the amount of uranium-238 that it contained when it was formed. (The amount that...
Cyclopropane rearranges to form propene in the gas phase. Part A If the initial cyclopropane concetration is 0.0540 M what is the cyclopropane concentration after 285 minutes? Express your answer with the appropriate units. CH2 HC-CH2 CH3-CH=CH2 μΑ ? Value Units The reaction is first order in cyclopropane and has a measured rate constant of 3.36 x 10-5s-1 at 720 K
At 500 oC cyclopropane (C3H6) rearranges to propene (CH3CHCH2) as shown by C3H6(g) -->CH3CHCH2(g). The reaction is first-order with a half-life of 17 minutes. How long will it take for the concentration of C3H6 to drop to 12.5% of its initial value at 500 oC?
At 500 ∘C, cyclopropane (C3H6) rearranges to propene (CH3−CH=CH2). The reaction is first order, and the rate constant is 6.7×10−4s−1. If the initial concentration of C3H6 is 5.50×10−2 M . What is the molarity of C3H6 after 30 min ? How many minutes does it take for the C3H6 concentration to drop to 1.00×10−2 M ? How many minutes does it take for 25% of the C3H6 to react? Express all the answers in two significant figures.
Cyclopropane rearranges to form propene in the gas phase. Constant Part A If the initial cyclopropane concetration is 0.0410 M, what is the cyclopropane concentration after 225 minutes? Express your answer with the appropriate units. CH HC-CH CH ---CH=CH, HA ? Value Units The reaction is first order in cyclopropane and has a measured rate constant of 3.36 x 10's-1 at 720 K. You may want to reference (Pages 635 - 641) Section 14.4 while completing this problem Submit Request...
1. Part: A The rate constant for a certain reaction is k = 6.00×10−3 s−1. If the initial reactant concentration was 0.550 M, what will the concentration be after 10.0 minutes? Part B: A zero-order reaction has a constant rate of 1.80×10−4M/s. If after 75.0 seconds the concentration has dropped to 7.50×10−2M, what was the initial concentration? 2. At 500 ∘C, cyclopropane (C3H6) rearranges to propane (CH3−CH=CH2). The reaction is first order, and the rate constant is 6.7×10−4s−1. If the...
At 500 ∘ C , cyclopropane ( C 3 H 6 ) rearranges to propene ( CH 3 −CH= CH 2 ). The reaction is first order, and the rate constant is 6.7× 10 −4 s −1 . If the initial concentration of C 3 H 6 is 5.50×10−2 M . Part A Part complete What is the half-life (in minutes) of this reaction? Express your answer using two significant figures. t 1/2 = 17 min SubmitPrevious Answers Correct Part...