a) P(a part is defective) = 0.10x0.08 + 0.30x0.06 + 0.60x0.03
= 0.044
b) Bayes' Theorem: P(A | B) = P(A & B) / P(B)
P(second machine | defective part) = P(second machine & defective) / P(defective)
= 0.3x0.06/0.044
= 0.4091
2. a) In a factory, parts are manufactured by three machines, M1, M2, and Ms in...
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