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2. a) In a factory, parts are manufactured by three machines, M1, M2, and Ms in proportions 10: 30: 60. The percentages of 8%
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Answer #1

a) P(a part is defective) = 0.10x0.08 + 0.30x0.06 + 0.60x0.03

= 0.044

b) Bayes' Theorem: P(A | B) = P(A & B) / P(B)

P(second machine | defective part) = P(second machine & defective) / P(defective)

= 0.3x0.06/0.044

= 0.4091

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