Question

1.2 A 100 Refer to til 120 V sine 1 kHz ell μΗ following RLC circuit, find Xc O 10H 1*10^-5H O 8.25 * 10^-10 H O 6.28 * 10^-3
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Answer #1

Answer: \large \circ 6.28*10^-3 H

Explanation: For a RLC circuit the maximum current is attained when XL  = X C

Now XL = WL   where W = 2\large \piX 1 kHz = 2000\large \pi and L= 1 \mu H = 10^-6 H

so XC= XL= 2000\large \pi X 10^-6 = 6.28 X 10^-3 H

Answer: 6.28 X 10^-3 H

Thank You.

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